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3 years ago

Mr.edwards buys 2 new knobs for each of his kitchen cabinets.the kitchen has 9 cabinets.how many knobs does he buy.

Mathematics

2 answers:

olchik [2.2K]3 years ago

5 0

18 Knobs
9 x 2 = 18

Digiron [165]3 years ago

3 0

He would have 18 knobs.

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IN THE 2000 UNITED STATES PRESIDENTIAL ELECTION, 59.3 MILLION WOMEN VOTED. THAT NUMBER WAS 56% OF THE NUMBER OF THE WOMEN WHO WE

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D - 15.4 million.

59.3m is 56% of 105.89m whereas 51.6m is 57% of 90.52m

105.89 - 90.52 = 15.37

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3 years ago

You have found a home that you are interested in purchasing. Instead of a conventional loan, you agree to pay the premium for th

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Answer:

$6,250

Step-by-step explanation:

Finances 95% of the loan.

So you have to pay 100% - 95% = 5% of the loan.

The amount of the home is listed at $125,000.

You have to pay 5% of this. So

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3 years ago

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3 years ago

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zimovet [89]

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3 years ago

In a certain Algebra 2 class of 30 students, 19 of them play basketball and 12 of them play baseball. There are 8 students who p

Alenkinab [10]

Answer:

Probability that a student chosen randomly from the class plays basketball or baseball is $\frac{23}{30}$ or 0.76

Step-by-step explanation:

Given:

Total number of students in the class = 30

Number of students who plays basket ball = 19

Number of students who plays base ball = 12

Number of students who plays base both the games = 8

To find:

Probability that a student chosen randomly from the class plays basketball or baseball=?

Solution:

$P(A \cup B)=P(A)+P(B)-P(A \cap B)$ ---------------(1)

where

P(A) = Probability of choosing a student playing basket ball

P(B) = Probability of choosing a student playing base ball

P(A \cap B) = Probability of choosing a student playing both the games

Finding P(A)

P(A) = $\frac{\text { Number of students playing basket ball }}{\text{Total number of students}}$

P(A) = $\frac{19}{30}$ --------------------------(2)

Finding P(B)

P(B) = $\frac{\text { Number of students playing baseball }}{\text{Total number of students}}$

P(B) = $\frac{12}{30}$ ---------------------------(3)

Finding $P(A \cap B)$

P(A) = $\frac{\text { Number of students playing both games }}{\text{Total number of students}}$

P(A) = $\frac{8}{30}$ -----------------------------(4)

Now substituting (2), (3) , (4) in (1), we get

$P(A \cup B)= \frac{19}{30} + \frac{12}{30} -\frac{8}{30}$

$P(A \cup B)= \frac{31}{30} -\frac{8}{30}$

$P(A \cup B)= \frac{23}{30}$

7 0

3 years ago