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3 years ago

Assuming that the pentagon is regular, what is the area of the shaded region below?

Mathematics

1 answer:

Rom4ik [11]3 years ago

5 0

I need the below to answer

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Find the coordinates of the image under the transformation (x – 4, y + 6) for ∆XYZ at X(-6, 1), Y(4, 0), Z(1, 3)

Afina-wow [57]

Answer:

I think b

Step-by-step explanation:

I prefer B but it also might be D

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3 years ago

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Solve the equation. 27x - 6 = 9x - 1

Evgesh-ka [11]

27x-6=9x-1
27x-9x =-1+6
18x = 5
x = 5/18

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3 years ago

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Which answer would it be?<br> A. Graph C<br> B. Graph B<br> C. Graph A<br> D. Graph D

Mkey [24]

Answer:

Step-by-step explanation:

y < 1/3x -4

The y intercept is -4

The slope is 1/3

y is less than so the line is dotted

y is less than so we colour below the line

Please vote for Brainliest and I hope this helps!

5 0

2 years ago

After studying the diagram shown, Michael makes the following conclusions:

inn [45]

Answer:

Therefore, Michael concludes option C)

C) $(DA)^{2}=(DG)^{2}+(AG)^{2}$

Step-by-step explanation:

Given:

1. DG = 3 and the area of square DEFG is 9.

2. AG = 4 and the area of square GHIA is 16.

3. DA = 5 and the area of square ABCD is 25.

So we have,

$(DG)^{2}=3^{2}=9\\ \\(AG)^{2}=4^{2}=16\\\\(DA)^{2}=5^{2}=25\\$

Now Add DG² and AG² we get

$(DG)^{2}+(AG)^{2}=9+16=25=(DA)^{2}$

Which is also called as Pythagoras theorem i.e

$(\textrm{Hypotenuse})^{2} = (\textrm{Shorter leg})^{2}+(\textrm{Longer leg})^{2}$

Therefore, Michael concludes option C)

C) $(DA)^{2}=(DG)^{2}+(AG)^{2}$

3 0

3 years ago

Y-3=5(x+1) convert from point slope to standard form

Alex777 [14]

Answer:

Y=5x+8

Step-by-step explanation:

Distribute then move 3 to other side and you get the answer.

3 0

3 years ago