Answer:
0.06
Step-by-step explanation:
Answer:
It will take <u><em>80 days</em></u> for the bull calf to reach a weight of 500 kilograms.
Step-by-step explanation:
Given:
The weight of a bull calf is 388 kilograms.
Now, to find the weight of bull calf of how long it will take to reach a weight of 500 kilograms, if it’s weight increases at a rate of 1 2/5 kilograms per day.
Required weight which to be increased = 500 - 388 = 112 kilograms.
Rate of weight increase = ![1\frac{2}{5}=\frac{7}{5}](https://tex.z-dn.net/?f=1%5Cfrac%7B2%7D%7B5%7D%3D%5Cfrac%7B7%7D%7B5%7D)
=
Thus, the time required = ![\frac{required\ weight}{rate\ of\ weight}](https://tex.z-dn.net/?f=%5Cfrac%7Brequired%5C%20weight%7D%7Brate%5C%20of%5C%20weight%7D)
=
=
<em>The time required = 80 days</em>.
Therefore, it will take 80 days for the bull calf to reach a weight of 500 kilograms.
Answer:
![\displaystyle \frac{d}{dx}[3x + 5x] = 8](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Bd%7D%7Bdx%7D%5B3x%20%2B%205x%5D%20%3D%208)
General Formulas and Concepts:
<u>Calculus</u>
Differentiation
- Derivatives
- Derivative Notation
Derivative Property [Multiplied Constant]: ![\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Bd%7D%7Bdx%7D%20%5Bcf%28x%29%5D%20%3D%20c%20%5Ccdot%20f%27%28x%29)
Basic Power Rule:
- f(x) = cxⁿ
- f’(x) = c·nxⁿ⁻¹
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
![\displaystyle y = 3x + 5x](https://tex.z-dn.net/?f=%5Cdisplaystyle%20y%20%3D%203x%20%2B%205x)
<u>Step 2: Differentiate</u>
- Simplify:
![\displaystyle y = 8x](https://tex.z-dn.net/?f=%5Cdisplaystyle%20y%20%3D%208x)
- Derivative Property [Multiplied Constant]:
![\displaystyle y' = 8\frac{d}{dx}[x]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20y%27%20%3D%208%5Cfrac%7Bd%7D%7Bdx%7D%5Bx%5D)
- Basic Power Rule:
![\displaystyle y' = 8](https://tex.z-dn.net/?f=%5Cdisplaystyle%20y%27%20%3D%208)
Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Differentiation
6/74 i think. So #banananutmuffin/#muffinsintotal