The probability of picking two black marbles from a box at random without replacement is 1091 . The probability of drawing a bla
ck marble first is 514 . What is the probability of picking a second black marble, given that the first marble picked was black?
2 answers:
<u><em /></u><em />The correct answer to the question above is 4/13. Below it shows how it's achieved...<u><em>
EQUATION:</em></u>
P(A|B) = <u>P(A ∩ B)
</u> P(B)
<u>
</u>Step 1: Identify
P(B) = 5/14
P(A ∩ B) = 10/91
<u>
</u>Step 2: Insert into the equation and Solve
10/91 ÷ 5/14
Use reciprocal to divide
10/91 × 14/5
Simplify the answer
140/455
Simplified (Final Answer)
4/13
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</u>
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</u>
Answer:
4/13
<em>This is the correct answer! I just took the test! Good luck!!</em>
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