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ICE Princess25 [194]

3 years ago

14

The probability of picking two black marbles from a box at random without replacement is 1091 . The probability of drawing a bla

ck marble first is 514 . What is the probability of picking a second black marble, given that the first marble picked was black?

2 answers:

Nana76 [90]3 years ago

5 0

<u><em /></u><em />The correct answer to the question above is 4/13. Below it shows how it's achieved...<u><em>

EQUATION:</em></u>
P(A|B) = <u>P(A ∩ B)
</u> P(B)
<u>
</u>Step 1: Identify
P(B) = 5/14
P(A ∩ B) = 10/91
<u>
</u>Step 2: Insert into the equation and Solve
10/91 ÷ 5/14
Use reciprocal to divide
10/91 × 14/5
Simplify the answer
140/455
Simplified (Final Answer)
4/13

<u>
</u>
<u>

</u>

EastWind [94]3 years ago

4 0

Answer:

4/13

<em>This is the correct answer! I just took the test! Good luck!!</em>

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Makovka662 [10]

Answer:

Explained below.

Step-by-step explanation:

The formula for average rate of change is:

$\frac{f(b) - f(a)}{b - a}$

1. $\frac{f(b) - f(a)}{b - a}$ = $\frac{f(2) - f(1)}{2 - 1}$ = $\frac{100 - 40}{2 - 1}$ = $\frac{70}{1}$ = 70

2. $\frac{f(b) - f(a)}{b - a}$ = $\frac{f(4) - f(2)}{4 - 2}$ = $\frac{180 -110}{4 - 2}$ = $\frac{70}{2}$ = 35

3. $\frac{f(b) - f(a)}{b - a}$ = $\frac{f(8) - f(6)}{8 - 6}$ = $\frac{350 -230}{8 - 6}$ = $\frac{120}{2}$ = 60

4. $\frac{f(b) - f(a)}{b - a}$ = $\frac{f(10) - f(8)}{10 - 8}$ = $\frac{390 -350}{10 - 8}$ = $\frac{40}{2}$ = 20

5. Their average speed was the greatest during the first to second hour.

6. Their average speed was the least during the eight to tenth hours.

7. $\frac{f(b) - f(a)}{b - a}$ = $\frac{f(10) - f(1)}{10 - 1}$ = $\frac{390 -40}{10 - 1}$ = $\frac{350}{9}$ = 38.89 or 38.9

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3 years ago

A bag contains five Green marbles three blue marbles six yellow marbles and four white marbles if you are drawn at random withou

Fantom [35]

Answer:

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Step-by-step explanation:

I dont really know what your asking but I need the points. if the question is asking what I'm thinking that should be correct

7 0

3 years ago

Can anyone help me solve this? Please and thank you!

AveGali [126]

It's the sum of a geometric sequence.

Let's rewrite it a bit:

$\displaystyle\\\sum_{n=1}^{10}8\left(\dfrac{1}{4}\right)^{n-1}=8\sum_{n=1}^{10}\left(\dfrac{1}{4}\right)^n\cdot \left(\dfrac{1}{4}\right)^{-1}=8\sum_{n=1}^{10}\left(\dfrac{1}{4}\right)^n\cdot 4=32\sum_{n=1}^{10}\left(\dfrac{1}{4}\right)^n$

And now let's calculate this sum $\displaystyle \sum_{n=1}^{10}\left(\dfrac{1}{4}\right)^n$ :

$S_n=\dfrac{a(1-r^n)}{1-r}\\\\a=\dfrac{1}{4}\\n=10\\r=\dfrac{1}{4}\\\\S_{10}=\dfrac{\dfrac{1}{4}\cdot\left(1-\left(\dfrac{1}{4}\right)^{10}\right)}{1-\dfrac{1}{4}}=\dfrac{\dfrac{1}{4}\cdot\left(1-\dfrac{1}{1048576}\right)}{\dfrac{3}{4}}=\dfrac{\dfrac{1048575}{1048576}}{3}=\dfrac{1048575}{3145728}=\\=\dfrac{349525}{1048576}$

Now let's calculate the initial sum:

$\displaystyle 32\cdot \sum_{n=1}^{10}\left(\dfrac{1}{4}\right)^n=32\cdot \dfrac{349525}{1048576}=\dfrac{349525}{32768}\approx10.67$

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2 years ago