The probability of picking two black marbles from a box at random without replacement is 1091 . The probability of drawing a bla
ck marble first is 514 . What is the probability of picking a second black marble, given that the first marble picked was black?
2 answers:
<u><em /></u><em />The correct answer to the question above is 4/13. Below it shows how it's achieved...<u><em>
EQUATION:</em></u>
P(A|B) = <u>P(A ∩ B)
</u> P(B)
<u>
</u>Step 1: Identify
P(B) = 5/14
P(A ∩ B) = 10/91
<u>
</u>Step 2: Insert into the equation and Solve
10/91 ÷ 5/14
Use reciprocal to divide
10/91 × 14/5
Simplify the answer
140/455
Simplified (Final Answer)
4/13
<u>
</u>
<u>
</u>
Answer:
4/13
<em>This is the correct answer! I just took the test! Good luck!!</em>
You might be interested in
If 1/3 of a birds eggs hatch and 2 eegs hatch the bird would have to have laid 6 eggs in total.
The sum of the angles of a quadrilaterals is 360 so 8s=360 s=45
Answer: i think 1/4
Step-by-step explanation: maybe i might be incorrect
An ordered pair of the inverse of f(x)D, (1.2)
Answer:
2x<14
Step-by-step explanation:
let that number be x. twice a number means, 2×that number.and now we are supposing that number is x. so 2×X =2x
and less than means <
so the expression becomes
2x<14.