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Elden [556K]
2 years ago
11

Find the union and interesection of each of the following A={3,6,9,12}, B ={6,8,9}

Mathematics
2 answers:
mart [117]2 years ago
5 0

Answer:

\huge\boxed{ A\ union \ B = \{3,6,8,9,12\}}

\huge\boxed{A\ intersection \ B = \{6,9\}}

Step-by-step explanation:

A = {3,6,9,12}

B = {6,8,9}

A∪B = {3,6,9,12} ∪ { 6,8,9}   [Union means all of the elements should be included in the set of A∪B]

=> A∪B = {3,6,8,9,12}

Now,

A∩B = {3,6,9,12} ∩ {6,8,9}  [Intersection means common elements of the set]

=> A∩B = {6,9}

Archy [21]2 years ago
4 0

Answer:

Hello,

The answer would be,

A union B = {3,6,9,12}

and A intersection B= {6,9}

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Volgvan

Answer:

The length side of the original square banner was 9 ft

Step-by-step explanation:

Let

x-----> the length side of the original square banner

we know that

The new area of the banner is equal to

91=(x+4)(x-2)

Solve for x

91=(x+4)(x-2)\\ \\91=x^{2}-2x+4x-8\\ \\x^{2}+2x-99=0

Solve the quadratic equation by graphing

The solution is x=9 ft

see the attached figure

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3 years ago
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natima [27]

Answer:

x=5

Step-by-step explanation:

That is your answer .

First you do 4x-3+3=2x+7+3

then,4x=2x+10,then

subtract 2x from both side

4x-2x=2x+10-2x

simplify

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simplfy and you get x=5

Hope this helps :)

4 0
3 years ago
LAST ATTEMPT! MARKING AS BRAINLIEST!! ( simplifying radicals)
klasskru [66]

\huge \bf༆ Answer ༄

Let's solve ~

\qquad \looparrowright \sf - 2 \sqrt{192 {k}^{4} }

\qquad \looparrowright \sf - 2 \sqrt{2 {}^{6} \times   3{k}^{4} }

\qquad \looparrowright \sf - 2 \times 2 {}^{3}  \times  {k}^{2}   \times \sqrt{3}

\qquad \looparrowright \sf  - 16 {k}^{2}  \sqrt{3}

Hence, the correct choice is D

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