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Sav [38]
3 years ago
7

1/1+sin theta + 1/1-sin theta

Mathematics
1 answer:
stealth61 [152]3 years ago
4 0
Short answer 2 * sec^2(theta)
\frac{1}{1 - sin(\theta)} +  \frac{1}{1 + sin(\theta)}
Find the common denominator
The common denominator is (1 - sin(theta) * (1 + sin(theta) )

Multiply each fraction's numerator and denominator by the common denominator

\frac{1 +sin(\theta)}{(1 - sin(\theta))(1 + sin(\theta))} + \frac{1 - sin(\theta))}{(1 + sin(\theta)) * (1 - sin(\theta)) }

Remove the brackets and cancel the sin(theta) terms in the numerator.
Combine the denominator

2 / (1 - sin^2(theta)) but 1 - sin^2(theta) = cos^2(theta)
2 / (cos^2 (theta) but 1/cos^2(theta) = sec^2(theta)
2 * sec^2 (theta) <<<<< Answer
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What is the solution to the system of equations below?
zvonat [6]

Answer:

D. (2, -1)

Step-by-step explanation:

6 0
2 years ago
Please help me with this math problem ASAP.
vazorg [7]

Answer: x = -4; x = -1; x = 3

see in this graph, at x = {-4; -1; 3} => y = 0

=> the zeros of the function are -4; -1; 3

Step-by-step explanation:

7 0
2 years ago
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The ratio of ages of kissi and esinam is 3:5 and esinam is 3:5 The sum of ages of all 3 is 147 years.whats the age difference be
Sergio039 [100]

Answer:

48 years.

Step-by-step explanation:

Consider the complete question is "The ratio of ages of kissi and esinam is 3:5 and that of esinam and lariba is 3:5. The sum of ages of all 3 is 147 years. whats the age difference between oldest and youngest ?"

It is given that

Kissi : Esinam = 3:5 = 9:15

Esinam : Lariba = 3:5 = 15:25

So, the combined ratio is Kissi : Esinam : Lariba = 9:15:25

Let ages of Kissi, Esinam, Lariba are 9x, 15x and 25x.

Sum of ages of all 3 is 147 years.

9x+15x+25x=147

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x=3

The value of x is 3. So, the age of all three are

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Since Lariba is oldest and Kissi is youngest, therefore, the difference between their ages is

75-27=48

Hence, difference between oldest and youngest is 48 years.

8 0
2 years ago
How to do part a &amp; b
nata0808 [166]
You can do part a using The Pythagoras theorem:-

30^2 = x^2 + 24^2

x^2 = 30^2 - 14^2 = (30+24)(30-24) =  324

x =  18
7 0
3 years ago
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Nut C fits on Bolt C. Nut B fits on Bolt B. Nut A fits on Bolt A. Bolt C is larger than Bolt B. Bolt A and Bolt B are exactly th
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Bolt A will fit Nut A and Nut B

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Nut C fits on Bolt C.

Nut B fits on Bolt B.

Nut A fits on Bolt A.

Bolt C is larger than Bolt B.

Bolt A and Bolt B are exactly the same.

Then we can say that Bolt A will fit Nut A and Nut B...

4 0
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