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Sav [38]
3 years ago
7

1/1+sin theta + 1/1-sin theta

Mathematics
1 answer:
stealth61 [152]3 years ago
4 0
Short answer 2 * sec^2(theta)
\frac{1}{1 - sin(\theta)} +  \frac{1}{1 + sin(\theta)}
Find the common denominator
The common denominator is (1 - sin(theta) * (1 + sin(theta) )

Multiply each fraction's numerator and denominator by the common denominator

\frac{1 +sin(\theta)}{(1 - sin(\theta))(1 + sin(\theta))} + \frac{1 - sin(\theta))}{(1 + sin(\theta)) * (1 - sin(\theta)) }

Remove the brackets and cancel the sin(theta) terms in the numerator.
Combine the denominator

2 / (1 - sin^2(theta)) but 1 - sin^2(theta) = cos^2(theta)
2 / (cos^2 (theta) but 1/cos^2(theta) = sec^2(theta)
2 * sec^2 (theta) <<<<< Answer
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Subtract 43 from both sides
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Divide both sides by -6
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Final answer: p=5
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2 years ago
Find the probability of at least 6 failures in 7 trials of a binomial experiment in which the probability of success in any one
ziro4ka [17]

The probability of at least 6 failures in 7 trials of a binomial experiment in which the probability of success in any one trial is 9% will be <u>0.000343311 %</u>

<h3>What is the probability?</h3>

Probability is synonymous with possibility. It is concerned with the occurrence of a random event.

Probability can only have a value between 0 and 1. Its simple notion is that something is very likely to occur. It is the proportion of favorable events to the total number of events.

No of failure,n = 7

No of trials,x≥6

A binomial probability is represented as;

\rm P(x) = nC_x p^z(1-p)^{n-r}

Substitute the given data;

P(x \geq 6) = 7C_6 \times 9^6 \times 91-9)^{7-6} +7C_7 (9)^7+(1-9)^{(7-7)}

\rm P(x \geq 6)  = 0.000000343311 \\\\ P(x \geq6)=0.000343311 \%

Hence,the probability of at least 6 failures in 7 trials of a binomial experiment in which the probability of success in any one trial is 9% will be <u>0.000343311 %</u>

To learn more about probability, refer to the link: brainly.com/question/795909.

#SPJ1

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Find the midpoint of points A(-7,-6) and B(1,-10) graphically.​
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-3, -8 i think lmk .
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