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d1i1m1o1n [39]
2 years ago
12

Find the probability of at least 6 failures in 7 trials of a binomial experiment in which the probability of success in any one

trial is 9%.
p=____%
Mathematics
1 answer:
ziro4ka [17]2 years ago
4 0

The probability of at least 6 failures in 7 trials of a binomial experiment in which the probability of success in any one trial is 9% will be <u>0.000343311 %</u>

<h3>What is the probability?</h3>

Probability is synonymous with possibility. It is concerned with the occurrence of a random event.

Probability can only have a value between 0 and 1. Its simple notion is that something is very likely to occur. It is the proportion of favorable events to the total number of events.

No of failure,n = 7

No of trials,x≥6

A binomial probability is represented as;

\rm P(x) = nC_x p^z(1-p)^{n-r}

Substitute the given data;

P(x \geq 6) = 7C_6 \times 9^6 \times 91-9)^{7-6} +7C_7 (9)^7+(1-9)^{(7-7)}

\rm P(x \geq 6)  = 0.000000343311 \\\\ P(x \geq6)=0.000343311 \%

Hence,the probability of at least 6 failures in 7 trials of a binomial experiment in which the probability of success in any one trial is 9% will be <u>0.000343311 %</u>

To learn more about probability, refer to the link: brainly.com/question/795909.

#SPJ1

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Step-by-step explanation:

The area of a rectangular field is given by the following formula:

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So applying the data from the problem, we have:

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5 0
3 years ago
Can someone help me here ASAP? this question is worth 20 points. will mark the brainliest, thank you so much in advanced.
worty [1.4K]

Answer:

1. a) (1-1) (1-2) (1-3) (2-1) (2-2) (3-1)

2. a) (5-1) (5-2) (5-3) (5-4) (5-5) (5-6)

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Step-by-step explanation:

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What proportion of a normal distribution corresponds to z scores greater than 1.04?
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