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Monica [59]
3 years ago
5

Please help ...........​

Mathematics
1 answer:
earnstyle [38]3 years ago
7 0
The answer is c.....
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The sum of the measures of ∠QRT and ∠TRS is 180∘. What is the measure of ∠TRS If ∠TRS = ∠QRT?​
Bad White [126]

Let the angles be x

  • ∠QRT = x
  • ∠TRS = x

We are taking both angles as x because they are equal!

\mathcal{∠QRT  + ∠TRS  = 180 \degree}

\tt \: x + x = 180 \degree

\tt \: 2x = 180 \degree

\tt \: x = 90 \degree

➪ <em>T</em><em>h</em><em>u</em><em>s</em><em>,</em><em> </em><em>T</em><em>h</em><em>e</em><em> </em><em>m</em><em>e</em><em>a</em><em>s</em><em>u</em><em>r</em><em>e</em><em> </em><em>o</em><em>f</em><em> </em><em>b</em><em>o</em><em>t</em><em>h</em><em> </em><em>a</em><em>n</em><em>g</em><em>l</em><em>e</em><em>s</em><em> </em><em>i</em><em>s</em><em> </em><em>9</em><em>0</em><em>°</em><em>.</em><em>.</em><em>.</em><em>~</em>

5 0
2 years ago
The school is 625 meters far from Alex house. It took him 15 minutes to go from home to school, and run back to home in 10 minut
Lynna [10]
His average speed was 50 m/min
8 0
3 years ago
If the perimeter of a square is 20, find the length of a diagonal
avanturin [10]

Answer:

7.07

Step-by-step explanation:

<h2><u>Length</u></h2>

a square has equal length on each side

hence is the perimeter is 20 it means that :

each side is 20/4 = 5

we can make a diagonal line which create 3 right angled triangles

2 sides of the triangle are 5 , this is the base and the height

to find the length we can make use of the Pythagoras theorem

c^2 = a^2 + b^2

c is the hypotenuse ( the diagonal;)

a and b are the opposite and adjacent

hence :

c^2 = 5 ^2 + 5^2

c^2 = 50

c = \sqrt{50}

c = 7.071

to 3sf

<h3><u>diagonal length  = 7.07</u></h3>

6 0
3 years ago
Megan reads 2 pages of a book each morning
Makovka662 [10]
It’s A because 2+3=5 and 5x7=35
8 0
3 years ago
Who wanna be friends???=)<br><br> Also what is 1+1? XD
stira [4]
Your answer would be 1+1=2

This took me a while to figure out
:)
Your welcome
Have a nice day

6 0
2 years ago
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