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zmey [24]
4 years ago
5

What is the acceleration due to gravity here on Earth?

Physics
1 answer:
slega [8]4 years ago
3 0
It would be because at the surface of the earth, the acceleration due to gravity is roughly 9.8m/s. so the answer would be D,
You might be interested in
A 36 N net force acts on an 9 kg rock. What is the acceleration of the rock? *
Anna007 [38]

Answer:

f=ma

therefore we have f=36N

                               m=9kg

a=f/m

36/9

=4m/s^2

Explanation:

3 0
3 years ago
A homeowner is trying to move a stubborn rock from his yard. By using a a metal rod as a lever arm and a fulcrum (or pivot point
pogonyaev

Answer:

L = 1.545 m

Explanation:

Let the total length of the rod is L

now the torque must applied on the other end of the rod so that it will balance the torque due to weight of rock on other side of fulcrum

so we will have

mg \times d = F(L - d)

so we have

325\times 9.8 \times 0.266 = F(L - 0.266)

F = 663 N

848 = 663(L - 0.266)

L = 1.545 m

6 0
3 years ago
What is the speed vfinal of the electron when it is 10.0 cm from charge 1?
fgiga [73]

Answer:

Two stationary positive point charges, charge 1 of magnitude 3.45 nC and charge 2 of magnitude 1.85 nC, are separated by a distance of 50.0 cm. An electron is released from rest at the point midway between the two charges, and it moves along the line connecting the two charges. What is the speed v(final) of the electron when it is 10.0 cm from

The answer to the question is

The speed v_{final} of the electron when it is 10.0 cm from charge Q₁

= 7.53×10⁶ m/s

Explanation:

To solve the question we have

Q₁ = 3.45 nC = 3.45 × 10⁻⁹C

Q₂ = 1.85 nC = 1.85 × 10⁻⁹ C

2·d = 50.0 cm

a = 10.0 cm

q = -1.6×10⁻¹⁹C

Also initial kinetic energy = 0 and

Initial electric potential energy = k\frac{qQ_1}{d} + k\frac{qQ_2}{d} = kq(\frac{Q_1+Q_2}{d})

Final kinetic energy due to motion = 0.5·m·v²

Final electric potential energy = k\frac{qQ_1}{a} + k\frac{qQ_2}{2d-a} = kq(\frac{Q_1}{a}+\frac{ Q_2}{2d-a})

From the energy conservation principle we have

0+ kq(\frac{Q_1+Q_2}{d})=0.5mv^2+  kq(\frac{Q_1}{a}+\frac{ Q_2}{2d-a})

Solving for v gives

v=\sqrt{\frac{kq(\frac{Q_1+Q_2}{d})-   kq(\frac{Q_1}{a}+\frac{ Q_2}{2d-a})}{0.5m}}

where k = 9.0×10⁹ and m = 9.109×10⁻³¹ kg

gives v =7528188.32769 m/s or 7.53×10⁶ m/s

v_{final} = 7.53×10⁶ m/s

6 0
4 years ago
1:
Ksenya-84 [330]

Answer:

Bowl will have maximum potential energy

Explanation:

It is the bowl that will have maximum potential energy.

It is because potential energy is high when both height and mass of the object is high.

Here in this case the bowl has maximum weight with maximum height except the tea cup but the potential weight of cup will not make much impact as its weight is very low.

6 0
3 years ago
Size relationships between parts of a whole are known as.
Stella [2.4K]

Answer:

proportion

Explanation:

hope it was helpful to you

then

plz mark me as brainlist

8 0
2 years ago
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