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saw5 [17]
3 years ago
13

Please Help!!! I have no idea :(

Physics
2 answers:
ollegr [7]3 years ago
8 0

Answer:

1. A. Force

2.

3. B. or C.

4. 1,000 N as well

Explanation:

1. Force is mass multiplied by acceleration. if force and mass stay constant, then according to that equation, the acceleration stays constant as well.

I couldn't figure out what number 2 is though. Sorry.

Harlamova29_29 [7]3 years ago
3 0

The value which must stay constant during these trial is:

  • <u>A. Force</u>

The best description of the motion of the animal is:

  • <u>B. The animal will move to the right due to an unbalanced force on the right</u>  

The thing which could be true about the difference between the rockets is:

  • <u>C. One rocket engine produces more force than the other </u>

The amount of force which the wall hits the sledgehammer is:

  • <u>C. 1000 N</u>

Force is simply defined as the mass of a body which is multiplied by the acceleration and according to the laws of physics, if there is a constant in the mass and force, then the acceleration would also remain constant.

Read more here:

brainly.com/question/24557735

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Which process requires water to gain 2260 joules of energy per gram?
yuradex [85]
Vaporization - Th<span>e amount of heat needed to convert unit mass of a liquid into vapor form without a change in temperature is called heat of vaporization. For water t</span><span><span>he heat of vaporization is 2260 Joules / gram</span> at its normal boiling point .</span>

4 0
3 years ago
A sprinter accelerates at 7.5 m/s from rest in 2.0 s, what distance did she go? (15 m)
a_sh-v [17]

Answer:

<em>The sprinter traveled a distance of 7.5 m</em>

Explanation:

<u>Motion With Constant Acceleration </u>

It's a type of motion in which the rate of change of the velocity of an object is constant.

The equation that rules the change of velocities is:

v_f=v_o+at\qquad\qquad [1]

Where:

a   = acceleration

vo = initial speed

vf  = final speed

t    = time

The distance traveled by the object is given by:

\displaystyle x=v_o.t+\frac{a.t^2}{2}\qquad\qquad [2]

Using the equation [1] we can solve for a:

\displaystyle a=\frac{v_f-v_o}{t}

The sprinter travels from rest (vo=0) to vf=7.5 m/s in t=2 s. Computing the acceleration:

\displaystyle a=\frac{7.5-0}{2}

a=3.75\ m/s^2

Now calculate the distance:

\displaystyle x=0*2+\frac{3.75*2^2}{2}

\displaystyle x=7.5\ m

The sprinter traveled a distance of 7.5 m

8 0
3 years ago
Consider a steel guitar string of initial length L=1.00L=1.00 meter and cross-sectional area A=0.500A=0.500 square millimeters.
erma4kov [3.2K]

Answer:

The extent to which it would stretch  is \Delta L = 0.015 \ m

Explanation:

From the question we are told that

    The initial length is  L = 1.00m

     The area is  A = 0.500 mm^2 = \frac{0.500}{1 *10^6} = 0.500*10^6 \ m^2

     The Young modulus of the steel is  Y = 2.0*10^{11} Pa

     The tension   is  T =1500 N

The Young modulus is mathematically represented as

       Y = \frac{\sigma}{e}

Where \sigma is the stress which is mathematically represented as

           \sigma = \frac{F}{A}  

Substituting values

            \sigma = \frac{1500}{0.500*10^{-6}}  

           \sigma = 3.0*10^9 N/m^2  

And  e is the strain which is mathematically represented as

            e = \frac{\Delta L}{L }

Where \Delta L The extension of the steel string

Substituting these into the equation above

             Y = \frac{3.0*10^9}{\frac{\Delta L}{L} }

Substituting values  

           2.0 *10^{11} = \frac{3.0*10^9}{\frac{\Delta L}{L} }

          \Delta L = \frac{3.0*10^9  * 1}{2.0 *10^{11}}

         \Delta L = 0.015 \ m

7 0
3 years ago
When your standing in a subway train and the train suddenly stops but your body continues to move forward what Newton law is it
Aleksandr-060686 [28]

Newton's first law. Inertia.

If it's moving, it tends to keep moving.

"Stopped" tends to stay put

5 0
4 years ago
Read 2 more answers
Calculating the acceleration of two people pulling a box with same force and angle.
Dmitriy789 [7]

Here as we can see there we be net horizontal force acting on it

F_x = F_1cos20 + F_2cos20

also we know that

F_1 = F_2 = 80 N

now we will have

F_x = 2(80cos20)

F_x = 150.35 N

now for net force of box we know

F_x - F_f = ma

150.35 - 100 = ma

20a = 50.35

a = 2.52 m/s^2

so acceleration of the box will be 2.52 m/s/s

7 0
3 years ago
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