Answer:
for the fill in the blanks
1- static
2-kinetic
3-coeffiecient
4-opposite to
5-sin theta
6-cos theta
im not sure however what to do with the top part or if its even part of what you need help with
Answer:
26.8 %
Explanation:
TH = 100°C = 100 + 273 = 373 K
Tc = 0°C = 273 K
The efficiency of the heat engine is given by


η = 0.268
η = 26.8 %
Thus, the efficiency of the heat engine is 26.8 %.
Answer:
<h2>122kg</h2>
Explanation:
Using the law of conservation of momentum which states that 'the sum of momentum of bodies before collision is equal to their sum after collision. The bodies will move together with a common velocity after collision.
Momentum = Mass * Velocity
<u>Before collision;</u>
Momentum of receiver m1u1= 0 kgm/s (since the receiver is standing still)
Momentum of the tackler
m2u2 = 2.60*122 = 317.2 kgm/s
where m2 and u2 are the mass and velocity of the tacker respectively.
Sum of momentum before collision = 0+317.2 = 317.2 kgm/s
<u>After collision</u>
Momentum of the bodies = (m1+m2)v
v = their common velocity
m1 = mass of the receiver
Momentum of the bodies = (122+m1)(1.30)
Momentum of the bodies = 158.6+1.30m1
According to the law above;
317.2 = 158.6+1.30m1
317.2-158.6 = 1.30m1
158.6 = 1.30m1
m1 = 158.6/1.30
m1 = 122kg
The mas of the receiver is 122kg
Answer:
1.41 m/s, 7.85 rad/s
Explanation:
We can start by calculating the tangential velocity, which is given by:

where
r = 18 cm = 0.18 m is the radius of the circumference
T = 0.8 s is the period
Substituting,

Now we can also calculate the angular velocity, which is given by:

where again,
T = 0.8 s is the period
Substituting,

The momentum of each cart is given by:

where
m is the mass of the cart
v is its velocity (at the bottom of the ramp)
To answer the problem, let's calculate the momentum of each of the 4 carts:
1)

2)

3)

4)

Therefore, the cart with greatest momentum is cart 3, so the right answer is
<span>- trial 3, because this trial has a large mass and a large velocity</span>