This is the concept of algebra, we are required to find a number,x, such that 87 decreased by three times a number is great than one hundred and sixty-five.
Supposed the number is x, three times the number will be:
3*x=3x
thus;
87-3x≥165
-3x≥165-87
-3x≥78
dividing both sides by -3 we get:
(-3x)/(-3x)≥78/(-3)
x≤-26
This implies that the number is less than or equal to 26
To solve this problem, we need to recognize that Harry's age is given as "n". We can use this value and the given information to write expressions representing each person's age.
For Example, Jo is 2 years older than Harry and Harry's age is represented by the variable n. This means that n (Harry's age) plus 2 would equal Jo's age. This can be represented by the expression: n +2.
Next, we know that Kate is twice as old as Jo, and Jo's age is represented by the expression n+2. This means that 2 times Jo's age would be equal to Kate's age, or Kate's age = 2(n+2) or 2n +4.
Therefore, your answer is that Jo's age is n + 2 and Kate's age is 2n + 4.
Hope this helps!
<h3>The worth after 4 years is $ 680.24</h3>
<em><u>Solution:</u></em>
<em><u>The formula for compound interest, including principal sum, is:</u></em>
Where,
A = the future value of the investment
P = the principal investment amount
r = the annual interest rate (decimal)
n = the number of times that interest is compounded per unit t
t = the time the money is invested
From given,
n = 1 ( since interest is compounded annually)
p = 500
t = 4
<em><u>Substituting the values we get,</u></em>
Thus the worth after 4 years is $ 680.24
The scale factor is:
So you divide the corresponding lengths and the ratio you get is the scale factor. Hope it helps!
M is equal to the value m
