I think you meant to say
(as opposed to <em>x</em> approaching 2)
Since both the numerator and denominator are continuous at <em>t</em> = 2, the limit of the ratio is equal to a ratio of limits. In other words, the limit operator distributes over the quotient:
Because these expressions are continuous at <em>t</em> = 2, we can compute the limits by evaluating the limands directly at 2:
Answer:
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Square root of (5-9)^2+(1+6)^2
Using equation of motion.
S = ut + (1/2)gt²
Where S = Height, t = time, g = acceleration due to gravity = 9.8 m/s²
time, t = 8 seconds
Since it was dropped from height, initial velocity, u = 0
S = 0*t + (1/2)gt²
S = (1/2)gt²
S = (1/2)*9.8*8² = 4.9 * 8 * 8 = 313.6
Therefore the ledge is 313.6 m tall.
Answer:
I don't understand too...
