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Nataly_w [17]
3 years ago
9

(1/(x-1))-(3/(x^2+2x-3))

%7B%7D%5E%7B2%7D%20%2B%202x%20-%203%20%7D%20" id="TexFormula1" title=" \frac{1}{x - 1} - \frac{3}{x {}^{2} + 2x - 3 } " alt=" \frac{1}{x - 1} - \frac{3}{x {}^{2} + 2x - 3 } " align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
ycow [4]3 years ago
4 0

\dfrac{1}{x-1}-\dfrac{3}{x^2+2x-3} \\\dfrac{1}{x-1}-\dfrac{3}{(x+3)(x-1)} \\\dfrac{1\cdot(x+3)-3}{(x+3)(x-1)} \\\dfrac{x+3-3}{(x+3)(x-1)} \\\dfrac{x}{(x+3)(x-1)}

Hope this helps.

r3t40

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