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Greeley [361]
3 years ago
13

In the game of​ "Between," two cards are dealt from a standard deck and not replaced. You then pick a third card from the deck.

To​ win, you must pick a card that has a value between the other two cards. The order of values is​ 2, 3,​ 4, 5,​ 6, 7,​ 8, 9,​ 10, J,​ Q, K,​ A, where the letters represent a​ jack, queen,​ king, and​ ace, respectively. Determine the probability of your winning if the first two cards dealt are a queen and an ace
Mathematics
1 answer:
SOVA2 [1]3 years ago
4 0
There are 52 cards in a standard deck of cards and four suits to the cards (hearts, clubs, spades, and diamonds). each suit has 13 cards in it. so if the cards that are placed on the table are a queen and an ace, then two cards are gone from the deck, leaving only 50 cards left. then you have to take out the rest of the queens and the aces which leaves you with 44 cards. of those 44 cards that are left, only 8 of them can be used to win the game. so the ration is 8:44 which can be reduced to 2:11
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( p + 6 ) + ( 8p + 2 )
victus00 [196]

Answer:

9p+8

Step-by-step explanation:

p+8p= 9p

6+2= 8

9p+8

4 0
2 years ago
Read 2 more answers
HELP NEED HELP !<br><br> 1 + 1 = ?
goldenfox [79]

Answer:

2  ;-;

Step-by-step explanation:

7 0
3 years ago
A marketing firm would like to test-market the name of a new energy drink targeted at 18- to 29-year-olds via social media. A st
Anon25 [30]

Answer:

(a) The probability that a randomly selected U.S. adult uses social media is 0.35.

(b) The probability that a randomly selected U.S. adult is aged 18–29 is 0.22.

(c) The probability that a randomly selected U.S. adult is 18–29 and a user of social media is 0.198.

Step-by-step explanation:

Denote the events as follows:

<em>X</em> = an US adult who does not uses social media.

<em>Y</em> = an US adult between the ages 18 and 29.

<em>Z</em> = an US adult between the ages 30 and above.

The information provided is:

P (X) = 0.35

P (Z) = 0.78

P (Y ∪ X') = 0.672

(a)

Compute the probability that a randomly selected U.S. adult uses social media as follows:

P (US adult uses social media (<em>X'</em><em>)</em>) = 1 - P (US adult so not use social media)

                                                   =1-P(X)\\=1-0.35\\=0.65

Thus, the probability that a randomly selected U.S. adult uses social media is 0.35.

(b)

Compute the probability that a randomly selected U.S. adult is aged 18–29 as follows:

P (Adults between 18 - 29 (<em>Y</em>)) = 1 - P (Adults 30 or above)

                                            =1-P(Z)\\=1-0.78\\=0.22

Thus, the probability that a randomly selected U.S. adult is aged 18–29 is 0.22.

(c)

Compute the probability that a randomly selected U.S. adult is 18–29 and a user of social media as follows:

P (Y ∩ X') = P (Y) + P (X') - P (Y ∪ X')

                =0.22+0.65-0.672\\=0.198

Thus, the probability that a randomly selected U.S. adult is 18–29 and a user of social media is 0.198.

6 0
3 years ago
Julio caught 3 fish weighing a total of 23 1/2 pounds. One fish weighed 9 5/8 pounds and another weighed 6 1/4 pounds. How much
Airida [17]
So we need to know what 23 1/2 + 9 5/8 + 6 1/4 is.
first, we need to make them into equivalent fraction. 
so...
23 1/2 can be 23 4/8
9 5/8 and
6 1/4 can be 6 2/8
let's add the whole numbers.
23 + 9 + 6 = 38
4/8 + 5/8 + 2/8 = 11/8 = 1 3/8
so 38 + 1 3/8 is 39 3/8
the answer is 39 3/8 pounds

4 0
2 years ago
Read 2 more answers
Quick timer
Kipish [7]
Answer is

geometric series
7 0
2 years ago
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