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Digiron [165]
3 years ago
12

What is the slope of the equation? y = 1/4x + 2

Mathematics
1 answer:
OLga [1]3 years ago
4 0

Answer:

1/4

Step-by-step explanation:

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Multiplying polynomials
notsponge [240]
3x^2+7x
18x^2-12x
-12x^3-8x^2
6x^3-18x^2+6x
5 0
3 years ago
Can you help me? I have to write the process of this.
Vadim26 [7]
Make a proportion of corresponding sides

Side AU corresponds to Side AB
Side UV corresponds to Side BC

Find AB by adding AU and UB
AU = 20x + 108
UB = 273
AB = 20x + 381

Make proportion
AU/AB = UV/BC
20x + 108/ 20x + 381 = 444/ 703

Cross Multiply
(20x + 108)(703) = (20x + 381)(444)
14,060x + 75,924 = 8,880x + 169,164

Solve for x
14,060x + 75,924 = 8,880x + 169,164
I'm sure you can figure this out
3 0
3 years ago
When subtracting decimals with the same sign you
Veronika [31]

Answer:

subtract

Step-by-step explanation:

let's say 1.1-1.1 same sign? yea. subtract.

6 0
3 years ago
The lengths of text messages are normally distributed with a population standard deviation of 6 characters and an unknown popula
ryzh [129]

Answer:

The 80% confidence interval for the population mean is between 28.32 characters and 31.68 characters.

Step-by-step explanation:

We have the standard deviation for the population, so we can use the normal distribution. If we had the standard deviation for the sample, we would have to use the t-distribution.

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.8}{2} = 0.1

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.5 = 0.9, so z = 1.282

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.282*\frac{6}{\sqrt{21}} = 1.68

The lower end of the interval is the sample mean subtracted by M. So it is 30 - 1.68 = 28.32 characters.

The upper end of the interval is the sample mean added to M. So it is 30 + 1.68 = 31.68 characters.

The 80% confidence interval for the population mean is between 28.32 characters and 31.68 characters.

6 0
3 years ago
Order from least ot greatest 2/5, 4%, 0.29, 27/100
eimsori [14]

You're answer:

2/5  4%  .29  27/100

8 0
3 years ago
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