Consider that the length and breadth of the bigger rectangle are L and B respectively. And the length and breadth of the bigger rectangle are l and b respectively.

The area of any rectangle is:

Area = Length × Breadth

The area of the bigger rectangle is:

Area of ABCD = L × B

The area of the smaller rectangle is:

Area of PQRS = l × b

Then the area of the remaining board will be:

Area of remaining board = Area of ABCD - Area of PQRS

= (L × B) - (l × b)

Thus, the area of the remaining board is [(L × B) - (l × b)].

8 0

3 years ago

What is the answer to 50/100 f $31.46=

FinnZ [79.3K]

Answer:62.92

Step-by-step explanation:

50/100f=.5f ... 31.46/.5=62.92 ... 62.92=f

4 0

4 years ago

Given that (in picture)...

GuDViN [60]

<h3>Answer: a = -3 and b = 5</h3>

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Work Shown:

Multiply top and bottom by $\sqrt{2}$ to rationalize the denominator

$\frac{10-\sqrt{18}}{\sqrt{2}}\\\\\frac{\sqrt{2}(10-\sqrt{18})}{\sqrt{2}*\sqrt{2}}\\\\\frac{\sqrt{2}*10-\sqrt{2}*\sqrt{18}}{\sqrt{2*2}}\\\\\frac{\sqrt{2}*10-\sqrt{2*18}}{\sqrt{4}}\\\\\frac{10\sqrt{2}-\sqrt{36}}{2}\\\\\frac{10\sqrt{2}-6}{2}\\\\\frac{-6+10\sqrt{2}}{2}\\\\\frac{2(-3+5\sqrt{2})}{2}\\\\-3+5\sqrt{2}\\\\$

We end up with something in the form $a+b\sqrt{2}$ where a = -3 and b = 5

7 0

3 years ago