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maw [93]
3 years ago
12

A hot-air balloon rises vertically at a constant rate of 8 m/s. A second hot-air balloon moves past the first hot-air balloon at

3 m/s downward relative to the first hot-air balloon. What is the velocity of the second hot-air balloon relative to the ground?
Mathematics
1 answer:
Lunna [17]3 years ago
8 0

The second hot-air balloon is moving 5 m/s

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Let X=[10 -3] and y=[-1 -5] then the distance between X and y is​
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-11 X +4+ 8X -4+ 3X equals
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rodikova [14]
Looking at the graph you can see that the domain of the function is:
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<u>Answer</u>

The first student was right.

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