Answer:
Step-by-step explanation:
To evaluate for such, the following comprehension is required,
Equation Required: Distance Formula: d(P, Q) = √ (x2 − x1)^2 + (y2 − y1)^2
Denote the configurations as the following,
(5, -1). (5, -4)
X1 Y1. X2. Y2
D(P, Q) = √(5 - 5)^2 + (-4 +1)^2. <== Since the double negative is present, the operation is acknowledged as positive.
D(P, Q) = √(0)^2 + (-3)^2
D(P, Q) = √9 = 3
Thus, the agglomerate distance between the points situated in the Cartesian plane is disclosed, and is, henceforth, disseminated as 03 units.
Answer:
9/169
Step-by-step explanation:
JQK of 4 suits = 12 cards
12/52x12/52=
3/13x3/13=
9/169
0.07 (5000-x) + 0.15x= 480
Solve for x
350-0.07x+0.15x=480
0.08x=130
X=1625 invested at 15%
(5000-1625)=3375 invested at 7%
Answer:
Possible derivation:
d/dx(a x + a y(x) + x a + y(x) a)
Rewrite the expression: a x + a y(x) + x a + y(x) a = 2 a x + 2 a y(x):
= d/dx(2 a x + 2 a y(x))
Differentiate the sum term by term and factor out constants:
= 2 a (d/dx(x)) + 2 a (d/dx(y(x)))
The derivative of x is 1:
= 2 a (d/dx(y(x))) + 1 2 a
Using the chain rule, d/dx(y(x)) = (dy(u))/(du) (du)/(dx), where u = x and d/(du)(y(u)) = y'(u):
= 2 a + d/dx(x) y'(x) 2 a
The derivative of x is 1:
= 2 a + 1 2 a y'(x)
Simplify the expression:
= 2 a + 2 a y'(x)
Simplify the expression:
Answer: = 2 a
Step-by-step explanation:
