Answer:
The equation of the line we want to write is 4y = -x + 22
Step-by-step explanation:
Here, we want to write the equation of a line
.
The standard equation of a straight line is given as:
y = mx + c
where m is the slope and c represents the y-intercept
Now, let’s look at the line y = 4x + 16
The slope of this line is 4
Now, the equation of the line we want to write is perpendicular to this line
When two lines are perpendicular, the product of their slopes = -1
Hence;
m * 4 = -1
m = -1/4
So the slope of the line we want to write is -1/4
Now, using the point-slope form for the new equation;
y-y1/x-x1 = m
From the point given (x1,y1) = (10,3)
Thus;
y-3/x-10 = -1/4
4(y-3) = -1(x - 10)
4y - 12 = -x + 10
4y = - x + 10 + 12
4y = -x + 22
It would be log7squared(7)
They are both proportional. 1:4 and 1:15
Answer:
Step-by-step explanation:
Slope -intercept form: y= mx +c, where m is the slope and c is the y-intercept.
Parallel lines have the same slope. Let's find the slope of the given line.
Given points: (-2, 0) and (0, -3)
slope of given line
Given that the y- intercept is 1, c= 1.
