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Georgia [21]
3 years ago
15

Simplify quantity 1 over 36 minus 1 over x squared all over 1 over 6 plus 1 over x.

Mathematics
1 answer:
Ne4ueva [31]3 years ago
7 0
 <span>[ (1 / 36) - (1 / x²) ] / [ (1 / 6) + (1 / x) ] 

[ (x² - 36) / 36x² ] / [ (x + 6) / 6x ] 

</span>remember that<span>: 
x² - 36 = (x + 6)(x - 6) 

so

[ (x+6)(x-6) / 36x² ] / [ (x + 6) / 6x ] 


[ (x+6)(x-6) / 36x² ] * [ 6x / (x + 6) ] 


6x / 36x² = 1 / 6x 


[ (x+6)(x-6) / 6x ] * [ 1 / (x+6) ] -------------------- > </span>(x - 6) / 6x<span>

The answer is </span>(x - 6) / 6x<span>

</span>
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3 years ago
Given that m/_a=40 and m/_b=61 find that the measure of angles x and y
brilliants [131]
Answer:
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Step-by-step explanation:
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7 0
1 year ago
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n parallelogram LMNO, MP = 21 m, LP = (y + 3) m, NP = (3y – 1) m, and OP = (2x – 1) m. What are the values of x and y? x = 10, y
seropon [69]

Answer:

The value of x = 11  and y = 2

Step-by-step explanation:

Given : parallelogram LMNO, MP = 21 m, LP = (y + 3) m, NP = (3y – 1) m, and OP = (2x – 1) m.

We have to find values of x and y.

Let P be the point of intersection of diagonals OM and LN.

In a parallelogram diagonal  bisects at right angles  and point of intersection divide diagonal in equal parts.

Thus, OP = MP and LP = PN

OP = MP , substitute the values, we get,

(2x-1) =  21

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⇒ y = 2  

Thus, the value of x = 11  and y = 2


8 0
4 years ago
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