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1 answer:
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Answer:
First mechanic worked 20 hours and second mechanic worked 5 hours
Step-by-step explanation:
Let the number of hours the first mechanic worked =
Let the number of hours the second mechanic worked =
Therefore, we can write 2 equations and then solve them simultaneously:
Rearranging the first equation:
and substituting into the second equation to find :
Now sub into the first equation to find
Therefore, first mechanic (a) worked 20 hours and second mechanic (b) worked 5 hours
So we just do
cost/number of people=cost per 1 person
so
(6p)/(3p^2)
remember that you can split it up and make ones
=
times 
=
times times 
= times 1 times 1=2/p
easy way is
remember that
(x^m)/(x^n)=x^(m-n)
so
(6p)(3p^2)=6/(3p=2/p=2p^-1
each member pays 2/p
cost/number of people=cost per 1 person
so
(6p)/(3p^2)
remember that you can split it up and make ones
easy way is
remember that
(x^m)/(x^n)=x^(m-n)
so
(6p)(3p^2)=6/(3p=2/p=2p^-1
each member pays 2/p