Discussion
The discriminate is b^2 - 4*a*c
The general equation for a quadratic is ax^2 + bx + c
In this equation's case
a = 1
b= -5
c = - 3
Solve
(-5)^2 - 4*(1)*(-3)
25 - (-12)
25 + 12
37
Note
Since the discriminate is > 0, the roots are real and different. The roots do exist and there are 2 of them.
Hello from MrBillDoesMath!
Answer:
One solution (z = -1)
Discussion:
-2(z+3)-z=-z-4(z+2) =>
-2z -6 -z = -z -4z - 8 =>
-3z -6 = -5z -8 => add 6 to both sides
-2z = -5z -2 => add 5z to both sides
3z = -5z +5z -3 =>
3z = -3 =>
z = -1
Thank you,
MrB
12 red counters
7 more red counters than yellow counters
12 - 7 = 5 yellow counters
Dara has 5 yellow counters.
The next four terms in the sequence are a + 6, a + 10, a + 14, a + 18. This is because you are adding 4 to what is being done to “a” each time. If you look at the pattern, you’ll see that 4 is being added and the “a” stays the same.
