I want you to imagine as you read this or you can draw through the help of my explanation and see yourself:
1↪Draw triangle ABC where BC>AC
2↪D is any point on AC such that CD=CB
3↪Roughly drawing , you can assume CD=CB and and join BD
4↪SO triangle ABC which is a big triangle is divided into Triangles ABD and BDC
5↪See in triangle BDC ,CD=CB so, base angles of isosceles triangle are equal:
<CDB=<CBD = x (assume) which means x is acute angle since CDB and CBD are are in same triangle with same measure and there can't be any two obtuse angle in any traingle. So x must be acute.
6↪Now see in traingle ABD,
<ADB=180-<CDB=180-x=obtuse angle
...check yourself ...just subtract any acute angle from 180 you will get only obtuse angle (ie angle greater than 90)
That means in triangle ABD , one angle ADB is obtuse which means remaining <ABD and < BAD are acute. [PROVED]
❇Main Concept Used Here:
↪In any triangle there can be maximum of one obtuse angle...so remaining two must be acute angle otherwise interior angles sum can't be equal to 180.
Answer:
g(-9) = 1
Step-by-step explanation:
g(-9) is the value of the function at x = -9
Go over the x = -9 and go up until you hit the blue line
Read the value of y
g(-9) = 1
Look up online "equation calculator" and it should be the first one to appear, "Symbolab" supper easy way to help you with problems!
Answer: 16g - 25h
4 (-6g - 10h) + 3h - 4 (- 3h - 10g)
-24g - 40h +3h +12h +40g
16g - 25h
Step-by-step explanation:
if this is wrong im sorry
