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KengaRu [80]
3 years ago
13

Jorge bought x tickets to attend a football game and a baseball game. The expression 8x + 62 represents the total cost of the fo

otball game, and 9x + 34 represents the total cost of the baseball game. How much more did the football game cost if Jorge bought 7 tickets for each game.
Mathematics
1 answer:
rusak2 [61]3 years ago
5 0

Answer:

21

Step-by-step explanation:

Let x be the amount of ticket for each game

Given

The expression 8x + 62 represents the total cost of the football game

The total coat for the.game will be

8(7)+62

= 56+62

= 118

If 9x + 34 represents the total cost of the baseball game. The total coat will be;

9(7)+34

= 63+34

=97

To know how much more football game costs, we will take the difference in their cost.

Difference = 118-97

Difference= 21

Hence football game costs 21 more than baseball

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Answer:

The correct option is (c).

Step-by-step explanation:

The complete question is:

The data for the student enrollment at a college in Southern California is:

                    Traditional          Accelerated            Total

                  Math-pathway     Math-pathway

Female              1244                       116                   1360

Male                  1054                       54                    1108

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We want to determine if the probability that a student enrolled in an accelerated math pathway is independent of whether the student is female. Which of the following pairs of probabilities is not a useful comparison?

a. 1360/2468 and 116/170

b. 170/2468 and 116/1360

c. 1360/2468 and 170/2468

Solution:

If two events <em>A</em> and <em>B</em> are independent then:

P(A|B)=P(A)\\\\\&\\\\P(B|A)=P(B)

In this case we need to determine whether a student enrolled in an accelerated math pathway is independent of the student being a female.

Consider the following probabilities:

P (F|A) = \farc{116}{170}\\\\P(A|F)=\frac{116}{1360}\\\\P(A)=\frac{170}{2468}\\\\P(F)=\frac{1360}{2468}

If the two events are independent then:

P (F|A) = P(F)

&

P (A|F) = P (A)

But what would not be a valid comparison is:

P (A) = P(F)

Thus, the correct option is (c).

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