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2 years ago

B-5=-2. Plz need answer asap b=what???plzzz6

Mathematics

1 answer:

ruslelena [56]2 years ago

7 0

Answer:

B=-2+5 collecting like terms

B=3 answer

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Plz no links and answers asap

JulijaS [17]

Answer:

10 is the evaluated answer.

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2 years ago

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Whích graph is generated by this table of values?

arlik [135]

Answer:

23132as

Step-by-step explanation:

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4 0

1 year ago

What is the measure of angle x?

aivan3 [116]

Answer:

83 is the measure of x.

Step-by-step explanation:

A triangle is equal to 180 degrees. So 180 - 53 - 44 = 83.

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1 year ago

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Expand using the properties and rules for logarithms

malfutka [58]

Consider expression $\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right).$

1. Use property

$\log_a\dfrac{b}{c}=\log_ab-\log_ac.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3x^2-\log_{\frac{1}{2}}2.$

2. Use property

$\log_abc=\log_ab+\log_ac.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3x^2-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+\log_{\frac{1}{2}}x^2-\log_{\frac{1}{2}}2.$

3. Use property

$\log_ab^k=k\log_ab.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3+\log_{\frac{1}{2}}x^2-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{\frac{1}{2}}2.$

4. Use property

$\log_{a^k}b=\dfrac{1}{k}\log_ab.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{2^{-1}}2=\\ \\=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x+\log_22=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x+1.$

Answer: correct option is B.

7 0

3 years ago

Geometry and perimeter help plz :(

Novay_Z [31]

Answer:

11.)4.79mi

12.)8cm

13.)10.6km

14.)5.93

15.)2yd

16.)5.41in

17)2y

18)2m

19)11.8yd

20)4.51km

Step-by-step explanation:

11.)15.8x2=31.6 31.6/6.6=4.79

12.)64/8=8

13.)26x2=54 54/4.9=10.6

14.)8.6x2=17.2 17.2/5.93

15.)2/1=2

16.)29.2/5.4=5.41

17)4/2=2

18)10/5=2

19)139.2/11.8=11.8

20)20.3/4.5=4.51

3 0

2 years ago