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3 years ago

15

Solve this inequality: x/13+6 less than or equal to 8

1 answer:

saveliy_v [14]3 years ago

8 0

$\frac{x}{13} +6 \leq 8 \\ \frac{x}{13} \leq 8-6 \\ \frac{x}{13} \leq 2 \\ x \leq 2*13 \\ x \leq 26$ for this problem you would first treat the inequality sign as an quals sign (unless you divide by -1), then you cansubtract 6 from both side to allow you to now multiply both sides by 13 to isolate the x, then you simplify (i simplified after each step but this is not required as long as you remeber that when you muliply or divide it is from all of both sides(if you did not simplify it would look like ((8-6)*13) )

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Which statement is true about the net and the solid it can form?

Sever21 [200]

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2 years ago

Please help me right now.

spin [16.1K]

$\sum\limits_{k=1}^{\infty}12\left(0.7\right)^{k-1}$

The infinite geometric series is converges if |r| < 1.

We have r = 0.7 < 1, therefore our infinite geometric series is converges.

The sum S of an infinite geometric series with |r| < 1 is given by the formula :

$S=\dfrac{a_1}{1-r}$

We have:

$a_1=12(0.7)^{1-1}=12(0.7)^0=12\\\\r=0.7$

Substitute:

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4 years ago

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3 years ago

Find f(x) and g(x) so that the function can be described as y=f(g(x)). Y=2/x^2+9

iragen [17]

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4 years ago

Whats 21.93 to 1 sighniificant figure

Mashutka [201]

Answer:

20 is the 1 significant figure to 21.93.

Step-by-step explanation:

Given:

The number 21.93 to 1 significant figure.

A <u>significant figure </u>is a digit in a number that gives you information about the numbers size.

Rounding to 1 significant figure means looking at the 1st digit of the number.

Here, the first digit is 2 and 2 is in tens place.

So, 2 in tens place gives us 20 as the size , thus next number next to 2 is 1.

So, on rounding to one significant figure we write it as 20.

Therefore, 20 is the 1 significant figure to 21.93.

7 0

4 years ago