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2 years ago

Which pair of angles has congruent values for the sin x° and the cos y°?

Mathematics

2 answers:

Ronch [10]2 years ago

6 0

Answer:

35°; 55°

Step-by-step explanation:

Suppose,

$\sin x=\cos y$

$\sin x = \sin (90-y)$ $(\because \cos \theta = \sin (90-\theta))$

$\implies x = 90 - y$

$\implies x + y = 90$

Hence, x and y must be complementary angles.

∵ 35° + 55° = 90°

35° + 145° = 180° ≠ 90°

35° + 70° = 105° ≠ 90°

35° + 35° = 70° ≠ 90°

Therefore, the pair of angles would be 35°; 55°.

Lesechka [4]2 years ago

5 0

This one is A. they are complementary

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2 years ago

Situation:

Gala2k [10]

Answer:

5.5 days (nearest tenth)

Step-by-step explanation:

Given formula:

$\sf N=N_0e^{-kt}$

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Given values:

$\sf N_0$ = 11 g
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Half-life: The time required for a quantity to reduce to half of its initial value.

To find the time it takes (in days) for the substance to reduce to half of its initial value, substitute the given values into the formula and set N to half of the initial mass, then solve for t:

$\begin{aligned}\sf N & = \sf N_0e^{-kt}\\\\\implies \sf \dfrac{11}{2} & = \sf 11e^{-0.125t}\\\\\sf \dfrac{1}{2} & = \sf e^{-0.125t}\\\\\sf \ln \left(\dfrac{1}{2}\right) & = \sf \ln e^{-0.125t\\\\\sf \ln \left(\dfrac{1}{2}\right) & = \sf -0.125t \ln e\\\\\sf \ln \left(\dfrac{1}{2}\right) & = \sf -0.125t(1)\\\sf t & = \sf \dfrac{\ln \left(\dfrac{1}{2}\right)}{-0.125}\\\\\sf t & = \sf 5.545177444...\\\\\sf t & = \sf 5.5\:\:days\:\:(nearest\:tenth)\end{aligned}$

Therefore, the substance's half-life is 5.5 days (nearest tenth).

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2 years ago

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2 years ago

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adelina 88 [10]

Answer:

Step-by-step explanation:

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~~~~~~~~~~~~~

1). ∠N ≅ ∠L Given

2). JK ≅ MK Given

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2 years ago