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bezimeni [28]
3 years ago
10

Please help answer either both or one question please! Best answer will get brainliest :)

Mathematics
2 answers:
Thepotemich [5.8K]3 years ago
8 0

Answer:

The answer is C I have the same assignment

Step-by-step explanation:

Yakvenalex [24]3 years ago
8 0
The answer you’re looking for it I C
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Find the point that lies on the line described by the equation below. y - 8 = - 3 (x-6)​
ohaa [14]

Answer:

B. (6, 8)

Step-by-step explanation:

To figure this out, you can plug in the coordinates to see if you get matching answers. Since you believe answer "B," is correct, we can check:

y - 8 = -3(x - 6)

8 - 8 = -3(6 - 6)

0 = -3(0)

0 = 0

<u>Since the answers match, that makes answer "B," correct.</u>

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Area and estimate helpp
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Solve this problem <br> 3d+d-7=25/4
creativ13 [48]
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alina1380 [7]
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3 0
3 years ago
Find the area of the shaded region.f(x)=4x+3x2−x3,g(x)=0<br> The area is _____.
Tasya [4]

Answer:

The answer is " \bold{\frac{7}{2}}"

Step-by-step explanation:

Given value:

\to f(x)=4x+3x^2-x^3\\\\\to g(x)=0

Find:

area=?

calculation:

\ Area = \int_{-1}^{0} -(4x+3x^2-x^3) dx  + \int_{0}^{1} (4x+3x^2-x^3) dx  \\\\

        =  -(2x^2+x^3- \frac{x^4}{4})_{-1}^{0} + (2x^2+x^3- \frac{x^4}{4})_{0}^{1}\\\\\\=  -( 2x^2+x^3- \frac{x^4}{4})_{-1}^{0} + (2x^2+x^3- \frac{x^4}{4})_{0}^{1}\\\\\\= ( 2- 1 -\frac{1}{4}) + (2+1- \frac{1}{4})\\\\\\=  ( \frac{8-4-1}{4}) + (\frac{8+4-1}{4})\\\\=  ( \frac{3}{4}) + (\frac{11}{4})\\\\=   \frac{3}{4} + \frac{11}{4}\\\\= \frac{11+3}{4}\\\\= \frac{14}{4}\\\\= \frac{7}{2}\\\\

7 0
3 years ago
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