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3 years ago

Please help answer either both or one question please! Best answer will get brainliest :)

Mathematics

2 answers:

Thepotemich [5.8K]3 years ago

8 0

Answer:

The answer is C I have the same assignment

Step-by-step explanation:

Yakvenalex [24]3 years ago

8 0

The answer you’re looking for it I C

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Find the point that lies on the line described by the equation below. y - 8 = - 3 (x-6)

ohaa [14]

Answer:

B. (6, 8)

Step-by-step explanation:

To figure this out, you can plug in the coordinates to see if you get matching answers. Since you believe answer "B," is correct, we can check:

y - 8 = -3(x - 6)

8 - 8 = -3(6 - 6)

0 = -3(0)

0 = 0

<u>Since the answers match, that makes answer "B," correct.</u>

4 0

3 years ago

Area and estimate helpp

Vikki [24]

Sorry. It's not clear. Plz tell me if there is 12 3/8in?

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2 years ago

Solve this problem <br> 3d+d-7=25/4

creativ13 [48]

If that 25/4 is a fraction them the answer is 53/4. Or in simplest form 3 5/16 or 3.3125

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3 years ago

Read 2 more answers

You have 6 dollars +12 pennies +to quarters + 4 dimes=2 nickels how much do you have

alina1380 [7]

You may have $26 I not a genius but this is easy

3 0

3 years ago

Find the area of the shaded region.f(x)=4x+3x2−x3,g(x)=0<br> The area is _____.

Tasya [4]

Answer:

The answer is " $\bold{\frac{7}{2}}$ "

Step-by-step explanation:

Given value:

$\to f(x)=4x+3x^2-x^3\\\\\to g(x)=0$

Find:

area=?

calculation:

$\ Area = \int_{-1}^{0} -(4x+3x^2-x^3) dx + \int_{0}^{1} (4x+3x^2-x^3) dx \\\\$

$= -(2x^2+x^3- \frac{x^4}{4})_{-1}^{0} + (2x^2+x^3- \frac{x^4}{4})_{0}^{1}\\\\\\= -( 2x^2+x^3- \frac{x^4}{4})_{-1}^{0} + (2x^2+x^3- \frac{x^4}{4})_{0}^{1}\\\\\\= ( 2- 1 -\frac{1}{4}) + (2+1- \frac{1}{4})\\\\\\= ( \frac{8-4-1}{4}) + (\frac{8+4-1}{4})\\\\= ( \frac{3}{4}) + (\frac{11}{4})\\\\= \frac{3}{4} + \frac{11}{4}\\\\= \frac{11+3}{4}\\\\= \frac{14}{4}\\\\= \frac{7}{2}\\\\$

7 0

3 years ago