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Naddika [18.5K]
3 years ago
12

A 12-sided sold has faces numbered 1 to 12. The table shows the results of rolling the solid 200

Mathematics
2 answers:
liraira [26]3 years ago
6 0

Answer:

it was 4/25

Step-by-step explanation:

Nonamiya [84]3 years ago
3 0
I think it has to be 20
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For what value of q is in the question -13(q+4)=7q+16​
Rufina [12.5K]

Answer:

q=-3 2/5

Step-by-step explanation:

First multiply -13 with (q+4)

-13q-52=7q+16

Now you have to change the order before = the numbers with q and after = the numbers without anything

-13q-7q=52+16

Remember that when you change positions the symbol too

Then solve it

-20q=68

Now u have to divide as i do

q=68/-20

you can simplify it

q=3 8/-20

Now divide by the greater divisor in this case is 4

q=3 2/-5

And organize it

q=-3 2/5

Never forget to do q=(answer)

Hopefully it helps.

5 0
3 years ago
Is y=2x-1 proportional
GREYUIT [131]
Since y=2x+1 does not pass through the origin (i.e. there exists the constant term of 1 ), the variables y and x are not directly proportional - though, they do have a linear relationship.
7 0
1 year ago
Plz help me plzzzzzzzzzz
Effectus [21]

Answer:

I think the answer is 7;

Step-by-step explanation:

All i did was subtract Q11 from all 4 of its sides;

11=4=7

7 0
2 years ago
Pattern: 0, 1, 3, 6, 10, 15, __<br> Explain the pattern of these numbers.
chubhunter [2.5K]

Answer:

21

Step-by-step explanation:

0 + 1 = 1

1 + 2 = 3

3 + 3 = 6

6 + 4 = 10

10 + 5 = 15

15 + 6 = 21

Each number is added to an increase of 1 - first add 1, then add 2, then add 3,etc

Not listed but next would be 21 + 7 = 28  

so it would be 0, 1, 3, 6, 10, 15, 21, 28

5 0
3 years ago
Which are the solutions of the quadratic equation? x2 = –5x – 3 –5, 0 StartFraction negative 5 minus StartRoot 13 EndRoot Over 2
boyakko [2]

<u>Given</u>:

The quadratic equation is x^{2}=-5 x-3

We need to determine the solutions of the quadratic equation.

<u>Solution</u>:

Let us solve the equation to determine the value of x.

Adding both sides of the equation by 5x and 3, we get;

x^{2}+5 x+3=0

The solution of the equation can be determined using quadratic formula.

Thus, we get;

x=\frac{-5 \pm \sqrt{5^{2}-4 \cdot 1 \cdot 3}}{2 \cdot 1}

x=\frac{-5 \pm \sqrt{25-12}}{2 }

x=\frac{-5 \pm \sqrt{13}}{2 }

Thus, the two roots of the equation are x=\frac{-5 + \sqrt{13}}{2 } and x=\frac{-5- \sqrt{13}}{2 }

Hence, the solutions of the equation are x=\frac{-5 + \sqrt{13}}{2 } and x=\frac{-5- \sqrt{13}}{2 }

6 0
3 years ago
Read 2 more answers
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