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2 years ago

3tanx3x=3 square rooted

Mathematics

1 answer:

torisob [31]2 years ago

6 0

Answer:

$\tan 3x=\frac{\sqrt{3} }{3} =\frac{1}{\sqrt{3} } =tan\frac{\pi }{6} =tan (n\pi +\frac{\pi }{6} )\\3x=n\pi +\frac{\pi }{6} =\frac{(6n+1)\pi }{6} \\x=\frac{(6n+1)\pi }{18} \\where~x~is~an~integer.$

Step-by-step explanation:

tan 3x=\frac{\sqrt{3} }{3} =\frac{1}{\sqrt{3} } =tan\frac{\pi }{6} =tan (n\pi +\frac{\pi }{6} )\\3x=n\pi +\frac{\pi }{6} =\frac{(6n+1)\pi }{6} \\x=\frac{(6n+1)\pi }{18} \\

where~x~is~an~integer.

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3 years ago

Are the irrational numbers closed under addition?

Arte-miy333 [17]

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Irrational numbers are not closed under addition.

Step-by-step explanation:

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3 years ago

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anyanavicka [17]

Step-by-step explanation:

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3 years ago

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g100num [7]

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3 years ago

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Vesnalui [34]

The Lagrangian is

$L(x,y,\lambda)=x+4y+\lambda(x^2+y^2-9)$

with critical points where the partial derivatives vanish.

$L_x=1+2\lambda x=0\implies x=-\dfrac1{2\lambda}$

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Substitute $x,y$ into the last equation and solve for $\lambda$ :

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3 years ago

3tanx3x=3 square rooted​

3tanx3x=3 square rooted