First solve the 2 inequalities for x:-
x > 0 or x <= -5
The last choice is the correct one.
Hello there, this problem is just basic addition, here is what it would look like
Solve it and we get 78.21
Answer:
- x + y ≤ 600
- 5x +7y ≥ 3500
- it is possible
Step-by-step explanation:
a) We can write two inequalities, one for the number of tickets, and one for the necessary revenue.
x + y ≤ 600 . . . . . . . limit imposed by available seating
5x +7y ≥ 3500 . . . . required revenue to meet expenses
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b) For x = 330, the first inequality puts one limit on y:
330 +y ≤ 600
y ≤ 270
And the second inequality puts another limit on y:
5(330) +7y ≥ 3500
7y ≥ 1850 . . . . subtract 1650
y ≥ 264.3 . . . . divide by 7
The number of tickets that must be sold to meet expenses is 265, which is less than the number that can be sold, 270. It is possible to meet expenses.
Question 1
Because the period is 2π, and the amplitude is 1obtain
f(x) = sin(x)
Because the horizontal shift is π, obtain
f(x) = sin(x - π)
Because the vertical shift is -4, obtain
f(x) = sin(x - π) - 4
Answer: 1. f(x) = sin(x - π) - 4
Question 2
The radius is 36/2 = 18 in.
1 revolution (360°) is the circumference, which is
2π(18) = 36π in
When the revolution is 62°, the distance traveled is
(62/360)*(36π) = (31/5)π in
Answer: 3. (31π)/5
Question 3.
Consider f(x) = 3cos(2x-π) - 1
f(0) = 3cos(-π) - 1 = -4
f(π/2) = 3cos(0) - 1 = 2
Rate of change = (2+4)/(π/2) = 12/π
From the graph, the rate of change of g(x) is
3/(π/2) = 6/π
Consider h(x) = sin(x) - 4
h(0) = 0 - 4 = -4
h(π/2) = 1 - 4 = -3
Rate of change = (-3+4)/(π/2) = 2/π
Therefore h(x) has the smallest rate of change
Answer: h(x)
Answer:
Angles and XWY and STR
Step-by-step explanation:
These two angels are alternate exterior angels because:
- They are on different sides of the transversal (the line intersecting the two parallel lines)
- They have the same angle measure
- They are exterior, meaning they are on the outside, not inside (interior)
Hope this helps!!! :)
