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never [62]
3 years ago
11

Can someone help me solve this and show me the work?

Mathematics
1 answer:
vodomira [7]3 years ago
5 0
 -8 < 2x + 4 < 10
<u>- 4          - 4   - 4</u>
<u>-12</u> < <u>2x</u> < <u>6</u>
  2       2     2
  -6 < x < 3
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What is the slope of the line passing through the points (-1,-7) and (-9, -2) ?​
Dominik [7]
The equation for slope is:
(y2 - y1) / (x2 - x1)

-2 -(-7) = 5
-9 -(-1) = -8

Slope of the line:

5/-8 or -5/8
7 0
2 years ago
Read 2 more answers
A student studying his classmates' cars' ages reports the 5-number summary as {1, 3, 4, 8, 20}. what is the iqr for his data?
timurjin [86]

IQR for the data {1, 3, 4, 8, 20} is 5.

Interquartile Range(IQR) for a data is defined as the difference between third quartile and first quartile.

denoted by  IQR=Q₃-Q₁              (Q₃ is third quartile and Q₁ is first quartile)

The five number summary of a data set is represented as

{minimum, first quartile , second quartile , third quartile , maximum}..…(1)

According to the question

{1, 3, 4, 8, 20}

On comparing it with equation   …(1)

minimum=1

Q₁ =3    , Q₂=4 , Q₃=8 , maximum =20

IQR=Q₃-Q₁

Substituting the values we get

IQR=8-3=5.

Therefore , Interquartile Range for the data {1, 3, 4, 8, 20} is 5.

Learn more about Inter Quartile Range here brainly.com/question/28037049

#SPJ4

3 0
1 year ago
NO LINKS!! Please help me with this problem​
iogann1982 [59]

{\qquad\qquad\huge\underline{{\sf Answer}}}

The given figure shows a vertical hyperbola with its centre at origin, and as we observe the figure, we can conclude that :

Length of transverse axis is :

\qquad \sf  \dashrightarrow \: 2b = 12

\qquad \sf  \dashrightarrow \: b = 6

length of conjugate axis is :

\qquad \sf  \dashrightarrow \: 2a = 8

\qquad \sf  \dashrightarrow \: a = 4

Equation of hyperbola ~

\qquad \sf  \dashrightarrow \:    \cfrac{ {y}^{2} }{ {b}^{2} } - \cfrac{  {x}^{2} }{ {a}^{2} }  = 1

plug in the values ~

\qquad \sf  \dashrightarrow \:    \cfrac{ {y}^{2} }{ {6}^{2} } - \cfrac{  {x}^{2} }{ {4}^{2} }  = 1

\qquad \sf  \dashrightarrow \:    \cfrac{ {y}^{2} }{ {36}^{} } - \cfrac{  {x}^{2} }{ {16}^{} }  = 1

5 0
1 year ago
Read 2 more answers
Write the equation of a circle with center (7.0) with radius 3.
harina [27]

Answer:

2.3

Step-by-step explanation:

so the 7.0 gets dived by the 3 because the radius is half of the circle.

5 0
3 years ago
Read 2 more answers
HELP WITH ALL PLZ I NEED HELP
alex41 [277]
1.) 16/100 and 0.16
2.) 7/10 and 0.7
3.) 6/10
4.) 73/100
5.) 6 9/10
6.)8 57/100
7.)0.70
8.)0.33
9.)7.20
10.)3.09
11.) 0.80
12.)0.48
13.)0.02
14.)0.55
15.)D
I hope all of these are correct and help
4 0
3 years ago
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