The type and number of solutions is (b) two imaginary solutions.
<h3>How to determine the type and number of solutions?</h3>
The equation is given as:
3x² + 5x + 5 = 0
A quadratic equation can be represented as:
ax^2 + bx + c = 0
Where, the discriminant (d) is
d = b^2 - 4ac
So, we have
d = 5^2 - 4 * 3 * 5
Evaluate
d = -35
The value of d is negative
This means that the equation has only imaginary solutions
Hence, the type and number of solutions is (b) two imaginary solutions.
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Hello from MrBillDoesMath!
Answer: x^2 - 6.5x + 10.5 = 0
Discussion:
If the roots are 3 and 3.5, then the quadratic equation is
(x -3 ) ( x - 3.5) = 0
or
x * (x - 3.5) - 3 (x - 3.5) = 0
or
X^2 - 3.5X - 3X + 3(3.5) = 0
or
x^2 - 6.5x + 10.5 = 0
Thank you,
MrB
2000 * .1 = 200 + 2000 = 2200 (First year)
2200 *.1 = 220 + 2200 = 2420 (second year )
2420* .1 = 242 + 2420 = 2662 (third year )
2662 * .1 = 266.2 + 2662 = 2928.2 (fourth year)
They spent $2928.2 on clothing for 4 years.
Answer:
-22
Step-by-step explanation:
9-31=-22
6/100× $85.25
x=$511.50 divided by 100
x=$5.1150 Or $5.12
rounded to the nearest cent