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mr Goodwill [35]
3 years ago
5

The area of a rectangle whose perimeter is a fixed 80 feet is given by A=40w - w2 , where w is the width of the rectangle. Deter

mine the width of the rectangle that gives the maximum area. What type of special rectangle is necessary to produce this maximum area? Justify.
Mathematics
1 answer:
Stolb23 [73]3 years ago
7 0

Answer:

Width=20 feet

Since Length=Width=20 feet, the rectangle is a Square.

Step-by-step explanation:

Area, A=40w - w^2

To determine the width of the rectangle that gives the maximum area, we take the derivative of A and solve for its critical point.

A'=40 - 2w\\$When A'=0\\40-2w=0\\40=2w\\w=20 feet

The width of the rectangle that gives the maximum area =20 feet.

Perimeter of a rectangle=2(l+w)

Perimeter of the rectangle=80 feet

2(l+w)=80

2l+2(20)=80

2l=80-40

2l=40

l=20 feet

Since the length and width are equal, the special type of rectangle that produces this maximum area is a Square.

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