Answer:
120ft.
Step-by-step explanation:
A garden is designed in the shape of a rhombus formed from 4 identical 30°-60°-90° triangles. The shorter distance across the middle of the garden measures 30 feet. What is the distance around the perimeter of the garden? 120ft.
Answer:
y = 6x
Explanation:
This question is asking you to write a linear equation in slope-intercept form, <u>y = mx + b,</u> where m is the slope and b is the y-intercept.
The y-intercept (where the line crosses the y-axis) is visibly 0. As for the slope, you can take two points, I'll use (0,0) and (0.1,0.6) to calculate it.
Slope = y - y/x- x
Slope = (0.6 - 0)/(0.1 - 0) = 0.6/0.1 = 6
Plug in 0 for b and 6 for m and you have an equation.
y = 6x + 0
y = 6x
Ex. 85+91= 176
176 divided by 2 = 88
Therefore the minimum score he can get is a 91
Answer:

Step-by-step explanation:
The first equation is 
The second equation is 
When we graph these two equations, <em>they will meet at a point which represent the solution of the two equations</em>.
We can solve the two equations simultaneously to determine their point of intersection.
Let us substitute the second equation into the first equation to get;

Multiply through by 2 to get;

Group similar terms to obtain;

Simplify;

Divide both sides by 3;

Put
into the second equation;



Therefore the graphs of the two functions intersect at (2,3)
See graph in attachment.