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4vir4ik [10]
3 years ago
12

Multiply and simplify: sq rt 7x ((sq rt x)-7sq rt. 7)

Mathematics
2 answers:
Dmitriy789 [7]3 years ago
5 0

Answer:

7x(√x - 7√7) Multiply √7x to "√x" and "-7√7" respectively: 

√7x*√x - 7√7*√7x 

First is to simplify: √7x² - 7√7²x 

Extract the squares: x√7 - 7*7√x 

Then, we simplify: x√7 - 49√x 

After simplifying the equation, I got the answer x√7 - 49√x.

Step-by-step explanation:

jarptica [38.1K]3 years ago
3 0
7x(√x - 7√7) Multiply √7x to "√x" and "-7√7" respectively: 
√7x*√x - 7√7*√7x 
First is to simplify: √7x² - 7√7²x 
Extract the squares: x√7 - 7*7√x 

Then, we simplify: x√7 - 49√x 
After simplifying the equation, I got the answer x√7 - 49√x.
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01.01) Rewrite the expression with rational exponents as a radical expression. 7 times x to the two thirds power cube root of th
jeka94

Answer:

(7x)^{\frac{2}{3} = (\sqrt[3]{7x})^2

Step-by-step explanation:

Given the expression (7x)^{\frac{2}{3}, to express this as a radical expressions, we'd apply the rule/law of indices that deals with converting expressions that has rational exponents into radical expressions.

The rule of indices to apply is: b^{\frac{m}{n}} = (\sqrt[n]{b})^m

To apply this to the expression, (7x)^{\frac{2}{3}, the denominator of the fraction of the exponent would determine the root, that is, cube root in this case. The numerator of the exponent would then determine the exponent of the radical expressions.

Thus:

(7x)^{\frac{2}{3} = (\sqrt[3]{7x})^2

6 0
3 years ago
Factor this expression completely.<br> 36y2 - 1
shtirl [24]

Answer:

(6y - 1)(6y + 1)

Step-by-step explanation:

To factorize completely, we may adopt the difference of 2 squares approach. The theory states that difference of two square  is the product of the difference of the number and the sum of the numbers.

Such that

a² - b² = (a - b) (a + b)

Hence 36y² - 1

= 6²y² - 1²

= (6y)² - 1²

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5 0
4 years ago
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Answer:

Exact Form:

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Decimal Form:

3.9

Mixed Number Form:

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Step-by-step explanation:

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Answer:

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4 years ago
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