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fredd [130]
3 years ago
7

Distance between (-6, -2) and (0,-1)

Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
5 0

Hey there! I'm happy to help!

To find the distance between two points, you square the difference of the x-values and square the difference of the y-values, add them, and then you square root it!

First, we'll add our two x-values.

-6-0= -6

We square it, which means to multiply it by itself.

-6(-6)=36        (If you multiply an even number of negative numbers, your answer is positive. Since we have two negative numbers, we get positive 36)

Now, we do the same with the y-values.

-2-(-1)=-1           (two negatives make it a plus, as in minus minus 1 is plus one.)

We square it.

-1(-1)=1              

Now, we add these x and y value differences.

36+1=37

Now, we find the square root using a calculator.

√37≈6.08

Have a wonderful day!

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Choose the congruence theorem that you would use to prove the triangles congruent.
Elena L [17]

<u><em>Answer:</em></u>

SAS

<u><em>Explanation:</em></u>

<u>Before solving the problem, let's define each of the given theorems:</u>

<u>1- SSS (side-side-side):</u> This theorem is valid when the three sides of the first triangle are congruent to the corresponding three sides in the second triangle

<u>2- SAS (side-angle-side):</u> This theorem is valid when two sides and the included angle between them in the first triangle are congruent to the corresponding two sides and the included angle between them in the second triangle

<u>3- ASA (angle-side-angle):</u> This theorem is valid when two angles and the included side between them in the first triangle are congruent to the corresponding two angles and the included side between them in the second triangle

<u>4- AAS (angle-angle-side):</u> This theorem is valid when two angles and a side that is not included between them in the first triangle are congruent to the corresponding two angles and a side that is not included between them in the second triangle

<u>Now, let's check the given triangles:</u>

We can note that the two sides and the included angle between them in the first triangle are congruent to the corresponding two sides and the included angle between them in the second triangle

This means that the two triangles are congruent by <u>SAS</u> theorem

Hope this helps :)

5 0
3 years ago
Read 2 more answers
I am having issues with this problem in math: 27x+33x-65x=y
Gekata [30.6K]

Answer:

Step-by-step explanation:

the answer would be -5x

6 0
3 years ago
3. A jet traveled at an average speed of 681 kilometers an hour. At that rate, how far did the jet go in 7 1/4 hours?​
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6 0
2 years ago
The sequence an = one third(3)n − 1 is graphed below: coordinate plane showing the points 2, 1; 3, 3; and 4, 9 Find the average
Maru [420]
The given sequence is:

a(n)= \frac{1}{3}  (3)^{n-1}

a(2)=1
a(3)=3
a(4)=9

We are to find the average rate of change between n=3 and n=4 for the given function.

Average rate of change = \frac{a(4)-a(3)}{4-3} = \frac{9-3}{1}=6

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8 0
3 years ago
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第 5 个问题 a multiple choice exam has 10 questions. each question has 3 possible answers, of which one is correct. a student knows
tatuchka [14]

The chances that the student was merely guessing is 1/3.

Bayes Theorem determines the conditional probability of an event A given that event B has already occurred.

denoted by

P(A/B)=\frac{P(A)*P(B/A)}{P(B)}

let A be the  event that the student knows the answer .

B be  the  event that the student does not knows the answer .

and

E be the event he gets answer correct .

According to the given question

P(A)=\frac{4}{10} \\\\ P(B)=1-\frac{4}{10} =\frac{6}{10}

Probability that the answer is correct ,given that he knows the answer is

P(E/A)=1

Probability that the answer is correct ,given that he guesses it is

P(E/B)=\frac{1}{3}   [as the MCQ has 3 options and only one is correct]

We need to find the probability that he guesses the answer given that it is correct.

Required probability P(B/E)=\frac{P(B)*P(E/B)}{P(A)*P(E/A)+P(B)*P(E/B)}

Substituting the values we get

P(B/E)=\frac{\frac{6}{10} *\frac{1}{3} }{\frac{4}{10} *1+\frac{6}{10} *\frac{1}{3} }

=\frac{6}{30}*\frac{30}{18}  \\ \\ =\frac{6}{18} \\ \\ =\frac{1}{3}

Therefore ,  the chances that the student was merely guessing is 1/3.

Learn more about Probability here brainly.com/question/13140147

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