Answer:
T₂=659.25 K
Explanation:
Given that
W= 25 J
Qr = 20 J
T₁ = 20⁰ = 20 +273 = 293 K
The minimum temperature of the hot reservoir = T₂
If the engine is Carnot engine then
Qa= W+ Qr
Qa=25 + 20 J
Qa= 45 J



T₂=659.25 K
Therefore the temperature of hot reservoir will be 659.25 K
Answer:
So -24.5 m merely means the depth of the base of the tower ie the ground from the top of the tower. So wrt the ground height of the tower = 24.5 m.
Explanation:
Answer:
17.6 m/s²
Explanation:
Given:
= 90 m/s (final velocity)
= 2 m/s (initial velocity)
Δt = 5s (change in time)
The formula for acceleration is:
= Δv / Δt
We can find Δv by doing
Δv =
- 
Replace the values
Δv = 90m/s - 2m/s
Δv= 88m/s
Using the equation from earlier, we can find the acceleration by dividing the average velocity by time.
= Δv / Δt
= 
acceleration = 17.6 
John's velocity is 20 m/s north.
Betty's velocity is 20 m/s south.
Their speeds are both 20 m/s.