Answer:

Explanation:
Apparent frequency that is received to the speeder is given as


here we know that

now we have


now the frequency that is received back from the speeder is given as



So difference is the frequency is given as


Sarcomere<span>The Sarcomere is the smallest functional unit of a myofibril (and also of the entire muscle) and contain the contractual elements between each pair of Z-discs.</span>
If im correct the answer is gravity
and wind resistance if you lift it fast
~~~hope this helps~~~
~~davatar~~
Answer:
a) v = 13.8 m / s
, b) a = 95.49 m / s²
, c) a force that goes to the center of the carnival ride and d) μ = 0.10
Explanation:
For this exercise we will use the angular kinematics relationships and the equation that relate this to the linear kinematics
a) reduce the magnitudes to the SI system
w = 1.1 rev / s (2pi rad / 1rev) = 6.91 rad / s
The equation that relates linear and angular velocity is
v = w r
v = 6.91 2
v = 13.8 m / s
b) centripetal acceleration is given by
a = v² / r = w² r
a = 6.91² 2
a = 95.49 m / s²
c) this acceleration is produced by a force that goes to the center of the carnival ride
d) Here we use Newton's second law
fr -W = 0
fr = W
μ N = mg
Radial shaft
N = m a
N = m w² r
μ m w² r = m g
μ = g / w² r
μ = 9.8 / 6.91² 2
μ = 0.10