Um u need to show what the options are.
Answer:
1240 m/s
Explanation:
[Do you mean 0.035 kg bullet?]
Since the momentum of the system is conserved,
Let u m/s be the initial velocity of the bullet
0.035u = 8.6(5+0.035)
u ~= 1237.1714 m/s
u = 1240 m/s (3 sig. fig.)
Answer:
<h2>
2.5 m</h2>
Explanation:
Load ( L ) = 500 N
Effort ( E ) = 200 N
Load distance ( LD ) = 3 m
Effort distance ( ED ) = ?
Now, Let's find the Effort distance ( ED )
We know that,
Output work = Input work
i.e L × LD = E × ED
plug the values

multiply the numbers

Swipe the sides of the equation

Divide both sides of the equation by 200

Calculate

Hope this helps..
best regards!!
Answer:
The Sun Crosses the Equator. on March 19, 20, or 21 every year. The September equinox occurs the moment the Sun crosses the celestial equator, this happens either on September 22, 23, or 24 every year.
Explanation:
The Sun Crosses the Equator. on March 19, 20, or 21 every year. The September equinox occurs the moment the Sun crosses the celestial equator, this happens either on September 22, 23, or 24 every year.
Answer:
a = (V2 - V1) / t equation for constant acceleration
if t the independent variable is placed on the abcissa or x-axis and V the dependent variable is placed on the ordinate or y-axis then the acceleration would be the slope at the point considered.