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ASHA 777 [7]
3 years ago
5

Stan does 178 J of work lifting himself 0.5 m. What is Stan’s mass? The acceleration of gravity is 9.8 m/s 2 . Answer in units o

f kg
Physics
2 answers:
svet-max [94.6K]3 years ago
8 0

Answer:

<h2>The mass is 36.33 kilograms.</h2>

Explanation:

The work is defined as the force needed to move an object a certain distance, if there's no change of position, there's no work.

In this case, the work is defined:

W=Fd

Where F is the weight defined with the following equation

F=W=mg

Now, we'll replace all given values and solve for m:

W=mgy\\178=m(9.8)(0.5)\\m=\frac{178}{4.9}=36.33 kg

Therefore, the mass is 36.33 kilograms.

Rom4ik [11]3 years ago
4 0
Work= (force)(distance)
178= m(9.81)x0.5
178=m(4.905)
178/4.905=m

His mass is 36.3 kg
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A rigid tank internal energy of fluid 800kJ. Fluid loses 500kJ of heat and padle wheel does 100kJ of work. Find final internal e
Nesterboy [21]

Answer:

 U₂ = 400 KJ      

Explanation:

Given that

Initial energy of the tank ,U₁= 800 KJ

Heat loses by fluid ,Q= - 500 KJ

Work done on the fluid ,W= - 100 KJ

Sign -

1.Heat rejected by system - negative

2.Heat gain by system - Positive

3.Work done by system = Positive

4.Work done on the system-Negative

Lets take final internal energy =U₂

We know that

Q= U₂ - U₁ + W

-500 = U₂ - 800 - 100

U₂ = -500 +900 KJ

U₂ = 400 KJ

Therefore the final internal energy = 400 KJ

6 0
3 years ago
Consider the uniform electric field E = (8.0ĵ + 2.0 ) ✕ 103 N/C. What is its electric flux (in N · m2/C) through a circular area
cluponka [151]

Answer:

5.09 x 10⁵ Nm²/C

Explanation:

The electric flux φ through a planar area is defined as the electric field Ε times the component of the area Α perpendicular to the field. i.e

φ = E A

From the question;

E = (8.0j + 2.0k) ✕ 10³ N/C

r = radius of the circular area = 9.0m

A = area of a circle = π r²           [Take π = 3.142]

A = 3.142 x 9² = 254.502m²

Now, since the area lies in the x-y plane, only the z-component of the electric field is responsible for the electric flux through the circular area.

Therefore;

φ = (2.0) x 10³ x 254.502

φ = 5.09 x 10⁵ Nm²/C

The electric flux is 5.09 x 10⁵ Nm²/C

4 0
2 years ago
The visible surface of the Sun, which is also the deepest layer we can see with our eyes, is in which region of the Sun?
Nina [5.8K]
It is the photosphere
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3 years ago
Capacitor C1 is initially charged to V1 and capacitor C2 is initially charged to V2. The capacitors are then connected to each o
o-na [289]

Answer:

<em>20.08 Volts</em>

Explanation:

<u>Parallel Connection of Capacitors</u>

The voltage across any two elements connected in parallel is the same. If the elements are capacitors, then each voltage is

\displaystyle V_1=\frac{Q_1}{C_1}

\displaystyle V_2=\frac{Q_2}{C_2}

They are both the same after connecting them, thus

\displaystyle \frac{Q_2}{C_2}=\frac{Q_1}{C_1}

Or, equivalently

\displaystyle Q_2=\frac{C_2Q_1}{C_1}

The total charge of both capacitors is

\displaystyle Q_t=Q_1\left(1+\frac{C_2}{C_1}\right)

We can compute the total charge by using the initial conditions where both capacitors were disconnected:

Q_t=V_{10}C_1+V_{20}C_2=25\cdot 24+13\cdot 11=743\ \mu C

Now we compute Q1 from the equation above

\displaystyle Q_1=\frac{Q_t}{\left(1+\frac{C_2}{C_1}\right)}=\frac{743}{\left(1+\frac{13}{24}\right)}=481.95\ \mu C

The final voltage of any of the capacitors is

\displaystyle V_1=V_2=\frac{481.95}{24}=20.08\ V

7 0
3 years ago
Whenever an object exerts a force on another object, the second object exerts a force o the same amount, but in the ______ direc
Brut [27]

Answer:

Opposite

Explanation:

Newton's third law of motion states that for every action there is an equal but opposite reaction.

Action-reaction force pairs make it possible for fishes to swim, birds to fly, cars to move etc,

For example, while driving down the road, a firefly strikes the windshield of a car (Action) and makes a quite obvious mess in front of the face of the driver (Reaction) i.e the firefly hit the car and the car hits the firefly.

The ultimately implies that, in every interaction, there is a pair of equal but opposite forces acting on the two interacting physical objects.

Hence, whenever any physical object exerts a force (action) on another physical object, the second physical object exerts a force (reaction) of the same amount, but acting in opposite direction to that of the first physical object.

4 0
3 years ago
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