Problem page the perimeter of a rectangular field is 358 yards. if the width of the field is 81 yards, what is its length?

A, B, and C are mutually exclusive. P(A) = .2, P(B) = .3, P(C) = .3. Find P(A ∪ B ∪ C). P(A ∪ B ∪ C) =

scoray [572]

Events are said to be mutually exclusive if they can not occur at the same time, that is, the probability of those events occurring at the same time is zero.
In the question given above,
P (A) = .2
P (B) = .3
P (C) = .3
P (A U B U C) = .2 + .3 + .3 = .8
Therefore, P (A U B U C) = 0.8.

3 0

4 years ago

Which of the following are solution to the equation below Check all that apply. (4x-1)^2=11

Juliette [100K]

Answer:

I think it's E and F. Let me know if I am wrong.

Step-by-step explanation:

4 0

4 years ago

The results of a mathematics placement exam at two different campuses of Mercy College follow: Campus Sample Size Sample Mean Po

Leona [35]

Answer:

$z=\frac{(33-31)-0}{\sqrt{\frac{8^2}{330}+\frac{7^2}{310}}}}=3.37$

$p_v =P(Z>3.37)=1-P(Z$

Comparing the p value with a significance level for example $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that the mean for the Campus 1 is significantly higher than the mean for the group 2.

Step-by-step explanation:

Data given

Campus Sample size Mean Population deviation

1 330 33 8

2 310 31 7

$\bar X_{1}=33$ represent the mean for sample 1

$\bar X_{2}=31$ represent the mean for sample 2

$\sigma_{1}=8$ represent the population standard deviation for 1

$\sigma_{2}=7$ represent the population standard deviation for 2

$n_{1}=330$ sample size for the group 1

$n_{2}=310$ sample size for the group 2

$\alpha$ Significance level provided

z would represent the statistic (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the mean for Campus 1 is higher than the mean for Campus 2, the system of hypothesis would be:

Null hypothesis: $\mu_{1}-\mu_{2}\leq 0$

Alternative hypothesis: $\mu_{1} - \mu_{2}> 0$

We have the population standard deviation's, and the sample sizes are large enough we can apply a z test to compare means, and the statistic is given by:

$z=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}}$ (1)

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

With the info given we can replace in formula (1) like this:

$z=\frac{(33-31)-0}{\sqrt{\frac{8^2}{330}+\frac{7^2}{310}}}}=3.37$

P value

Since is a one right tailed test the p value would be:

$p_v =P(Z>3.37)=1-P(Z$

Comparing the p value with a significance level for example $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that the mean for the Campus 1 is significantly higher than the mean for the group 2.

5 0

3 years ago

What is the approximate volume if this cone 9cm by 15cm

ArbitrLikvidat [17]

Hello there, and thank you for asking your question here on brainly.

Short answer: A. 1272 cm³

Why?

When finding the volume of a cone, you use the formula V = πr²h/3. R = 9, H = 15. V = π9²15/3 9² = 81 | 15 / 3 = 5 | 3.14 * 81 = 254.34 | 254.34 * 5 = 1271.2 1272 rounded.

Hope this helped you! ♥

5 0

3 years ago

How are the triangles congruent ? AAS , AA , ASA , SAS , or Not enough information

Karolina [17]

I have the answer. The answer is AAS

5 0

3 years ago