Translate the variable expression into a word phrase: 2•(3-X)

How in the world do I do this can somebody help please.

ValentinkaMS [17]

Answer:

Bl^2+4Bl*Fh

Step-by-step explanation:

I'm not quite certain what "draw a net" means here. But for part b, we are doing the formula. The bottom part is a square(assumingly so take this with a grain of salt), thus making the base equal to 3*3 cm or 9 cm^2. The triangular faces are each 3*2.24 cm or 6.72 cm^2. We then multiply this by 4 to get 26.88. Thus, the equation is Bl^2(Base length squared)+Bl*Fh(Face height, I forgot the official name sorry about that)*4 for part b.

5 0

2 years ago

Please solve e e eee

quester [9]

Answer:

C.

Step-by-step explanation:

Multiply both sides by 15, which gives you r≥-75

Since the graph has to go in the direction of numbers greater than -75, that would be -74, -73, -72, etc. So, it is C.

8 0

2 years ago

A Gardner wants to add 39 pounds of nutrient a and 16 pounds of nutrient b to her garden. Each bag of brand x provides 3 pounds

ehidna [41]

Answer:

5 bags of brand x and 6 bags of brand y.

Step-by-step explanation:

Nutrient requirement for the garden:

39 pounds of nutrient a and

16 pounds of nutrient b

Component of each bag of brand x:

3 pounds of nutrient a and 2 pounds of nutrient b

Therefore, 5 bags of brand x will contain 15 pounds of nutrient a and 10 pounds of nutrient b

Component of each bag of brand y:

4 pounds of nutrient a and 1 pound of nutrient b

Therefore, 6 bags of brand y will contain 24 pounds of nutrient a and 6 pounds of nutrient b

Altogether, she should buy 5 bags of brand x and 6 bags of brand y to meet the nutrient requirement of the garden

3 0

2 years ago

Suppose r(140°, P)(A) = B and (RPD←→∘RPC←→)(A) = B, what is m∠CPD?

NISA [10]

An angle bisector divides an angle into two equal halves.

The measure of angle $\angle CPD$ is 70 degrees

The complete question is an illustrates the concept of angle bisector;

Where:

$\angle RPD = 140^o$ , and line PC bisects $\angle RPD$

Because line PC bisects $\angle RPD$ , then it means that the measure of RPD is twice the measure of CPD:

So, we have:

$\angle RDP = 2 \times \angle CPD$

Substitute $\angle RPD = 140^o$

$140^o = 2 \times \angle CPD$

Divide both sides by 2

$70^o = \angle CPD$

Apply symmetric property of equality:

$\angle CPD = 70^o$

Hence, the measure of angle $\angle CPD$ is 70 degrees

Read more about angle bisectors at:

brainly.com/question/12896755

5 0

2 years ago

For each pair figures, find the ratio of the area of the first figure to the area of the second. 14mm 7mm

Paraphin [41]

The ratio of the area of the first figure to the area of the second figure is 4:1

<h3>Ratio of the areas of similar figures </h3>

From the question, we are to determine the ratio of the area of the first figure to the area of the second figure

The two figures are similar

From one of the theorems for similar polygons, we have that

If the scale factor of the sides of two similar polygons is m/n then the ratio of the areas is (m/n)²

Let the base length of the first figure be ,m = 14 mm

and the base length of the second figure be, n = 7 mm

∴ The ratio of their areas will be

$(\frac{14 \ mm}{7 \ mm})^{2}$

$= \frac{196 \ mm^{2} }{49\ mm^{2} }$

$=\frac{4}{1}$

= 4:1

Hence, the ratio of the area of the first figure to the area of the second figure is 4:1

Learn more on Ratio of the areas of similar figures here: brainly.com/question/11920446

8 0

1 year ago