The function that has a vertex on the y-axis is f(x) = (x - 2)(x + 2)
<h3>How to determine the function?</h3>
For a function to have its vertex on the y-axis, then the coordinate of the vertex must be:
(h,k) = (0,y)
A quadratic function is represented as:
f(x) = (x - h)^2 + k
So, we have:
f(x) = (x - 0)^2 + k
Evaluate
f(x) = x^2 + k
From the list of options, we have:
f(x) = (x - 2)(x + 2)
Expand
f(x) = x^2 - 4
Hence, the function that has a vertex on the y-axis is f(x) = (x - 2)(x + 2)
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Answer:
x = 8.5
Step-by-step explanation:
I got this answer by assuming the triangles were congurent, if they are not, the answer may vary.
first, make an equation:
x + 8 = 3x - 9
bring 3x to the other side, by subtracting it
-2x + 8 = -9
Subtract 8
-2x = -17
divide by -2
x = 8.5
Then, just sub x into the formulas
Answer:
97.8
Step-by-step explanation:
add together 97.3 +0.5
Answer:
32x
Step-by-step explanation:
Distribute the -8x to the (-4)