B=3 v/h solve for V, Middle School Math

Help me please with the question in the photo

Marianna [84]

Answer:

i think that the correct answer would be the second one

Step-by-step explanation:

i am so so sorry if the answer is wrong

hope this helps

plz mark brainliest

and plz hit the thanks button

8 0

2 years ago

Please help me question attached below:)))

atroni [7]

Answer:

D(5, 4), E(14, 7), M(9.5, 5.5)

Step-by-step explanation:

As AD = 1/4AB and DE ║ AC, the ratio CE/CB = 1/4, or CE = 1/4CB

Find the coordinates of D:

x = 1 + 1/4(17 - 1) = 1 + 4 = 5
y = 5 + 1/4(1 - 5) = 5 - 1 = 4

Find the coordinates of E:

x = 13 + 1/4(17 - 13) = 13 + 1 = 14
y = 9 + 1/4(1 - 9) = 9 - 2 = 7

Find the coordinates of the midpoint M of DE:

x = (5 + 14)/2 = 19/2 = 9.5
y = (4 + 7)/2 = 11/2 = 5.5

8 0

2 years ago

First make a substitution and then use integration by parts to evaluate the integral. (Use C for the constant of integration.) x

e-lub [12.9K]

Answer:

$(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C$

Step-by-step explanation:

Ok, so we start by setting the integral up. The integral we need to solve is:

$\int x ln(5+x)dx$

so according to the instructions of the problem, we need to start by using some substitution. The substitution will be done as follows:

U=5+x

du=dx

x=U-5

so when substituting the integral will look like this:

$\int (U-5) ln(U)dU$

now we can go ahead and integrate by parts, remember the integration by parts formula looks like this:

$\int (pq')=pq-\int qp'$

so we must define p, q, p' and q':

p=ln U

$p'=\frac{1}{U}dU$

$q=\frac{U^{2}}{2}-5U$

q'=U-5

and now we plug these into the formula:

$\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int \frac{\frac{U^{2}}{2}-5U}{U}dU$

Which simplifies to:

$\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int (\frac{U}{2}-5)dU$

Which solves to:

$\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\frac{U^{2}}{4}+5U+C$

so we can substitute U back, so we get:

$\int xln(x+5)dU=(\frac{(x+5)^{2}}{2}-5(x+5))ln(x+5)-\frac{(x+5)^{2}}{4}+5(x+5)+C$

and now we can simplify:

$\int xln(x+5)dU=(\frac{x^{2}}{2}+5x+\frac{25}{2}-25-5x)ln(5+x)-\frac{x^{2}+10x+25}{4}+25+5x+C$

$\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}-\frac{5x}{2}-\frac{25}{4}+25+5x+C$

$\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C$

notice how all the constants were combined into one big constant C.

7 0

3 years ago

Derek and Mia place two green marbles and one yellow marble in a bag. Somebody picks a marble out of the bag without looking and

Ahat [919]

Step-by-step explanation:

With each draw, the probability of selecting a green marble is 2/3 and the probability of selecting a yellow marble is 1/3.

To pick two of the the same color, they can either pick green twice or yellow twice.

P = (2/3)(2/3) + (1/3)(1/3)

P = 5/9

To pick two different colors, they can either pick green first then yellow, or yellow first then green.

P = (2/3)(1/3) + (1/3)(2/3)

P = 4/9

Expected value for Derek is:

D = (5/9)(-1) + (4/9)(1)

D = -1/9

The expected value for Mia is:

M = (5/9)(1) + (4/9)(-1)

M = 1/9

5 0

3 years ago

Solve for x. •4 •3.6 •3 •4.8

AnnyKZ [126]

Answer:

according to theorm 8 of basic geometry the answer is 6

5 0

2 years ago