So we are given two points that the line crosses, the origin and (9, -3), we can calculate the slope m of the line with these data, dividing the y segment by the x segment:
m = (-3 - 0)/(9 - 0) = -3/9
m = -1/3
then we can use the point slope line equation to find the line equation, lets use the point origin (0,0) to do so:
y - y1 = m(x - x1), where x1, y1 are the coordinates of a point that the line crosses:
y - 0 = (-1/3)(x - 0)
y = <span>(-1/3)x
so this is the equation of the line, slope -1/3 and y intercept 0</span>
Answer:
you should take the numeric value _16 to right side.
Answer:
6.7 units
Step-by-step explanation:
The distance between two points can be found using the formula below:
Thus, distance between (-1, 2) and (2, -4)
![= \sqrt{( - 4 - 2)^{2} + { [2-(-1) ]}^{2} }](https://tex.z-dn.net/?f=%20%3D%20%20%5Csqrt%7B%28%20-%204%20-%202%29%5E%7B2%7D%20%2B%20%20%7B%20%5B2-%28-1%29%20%5D%7D%5E%7B2%7D%20%20%7D%20)
= 6.7 units (nearest tenth)
Additional:
For a similar question on distance between points, do check out the following!
A)
x^2 - 6x + c = - 5 + c
using a^2 - 2ab + b^2 = (a-b)^2
so
6x = 2 * x * 3
so
c = 9
Answer
c = 9
b)
substitute c = 9
x^2 - 6x + 9 = - 5 + 9
(x - 3)^2 = 4
Answer:
(x - 3)^2 = 4
c) solve for x
(x - 3)^2 = 4
(x - 3)^2 = 2^2
so
x - 3 = 2
x = 5
and
x - 3 = -2
x = 1
Answer: x = 1 , 3
