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3 years ago

Deserts advance linearly, in easily mappable patterns. True False

2 answers:

7 0

It is false that deserts advance linearly, in easily mappable patterns.
Deserts don't really have a pattern when they are advancing - there are so many ways they can do this.

zvonat [6]3 years ago

6 0

This answer is false.

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Each day Mrs. Yoder assigns 15 addition and 12 multiplication problems as homework. What is the total number of addition and mul

schepotkina [342]

Answer:

27 each day

Step-by-step explanation:

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2 years ago

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I need help on this.

den301095 [7]

Answer:

yes

Step-by-step explanation:

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3 years ago

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Does anyone have a word problem idea for this equation 1.25x = 0.75x + 50

PSYCHO15rus [73]

Answer: Keke, do you love me? Are your riding?

Idk either.

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3 years ago

Each morning Rin rides 1.5 miles to school and then rides home in the afternoon. Later in the evening, she rides to the park and

brilliants [131]

Answer:

Last equation given in the list of possible answers:

5 ( 1.5 + 1.5 + x ) = 25

Step-by-step explanation:

We need to include in the total addition of miles ridden during the week:

a) 1.5 miles to the school

b) 1.5 miles from school back home

c) x miles for the evening ride

so for the miles ridden per day we have: "1.5 +1.5 + x"

Now, since per week she does 5 days like this, then we need to multiply the expression above by 5 in order to total the number of miles she rides weekly (25 miles)

5 ( 1.5 + 1.5 + x ) = 25

And we can use this equation to find the amount "x" that Rin rides in the evening.

7 0

3 years ago

A $250,000 home loan is used to purchase a house. The loan is for 30 years and has a 5.4% APR. Use the amortization formula to d

wlad13 [49]

$\bf ~~~~~~~~~~~~ \textit{Amortized Loan Value}
\\\\
pymt=P\left[ \cfrac{\frac{r}{n}}{1-\left( 1+ \frac{r}{n}\right)^{-nt}} \right]
\\\\\\
~~~~~~
\begin{cases}
P=
\begin{array}{llll}
\textit{original amount deposited}\\
\end{array}\to &250000\\
pymt=\textit{periodic payments}\\
r=rate\to 5.4\%\to \frac{5.4}{100}\to &0.054\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{since the payments are}\\
\textit{monthly, then twelve}
\end{array}\to &12\\
t=years\to &30
\end{cases}
$

$\bf pymt=250000\left[ \cfrac{\frac{0.054}{12}}{1-\left( 1+ \frac{0.054}{12}\right)^{-12\cdot 30}} \right]
\\\\\\
pymt=250000\left[ \cfrac{0.0045}{1-\left( 1.0045\right)^{-360}} \right]
\\\\\\
pymt\approx 250000\left[ \cfrac{0.0045}{0.80138080852472389274} \right]$

8 0

3 years ago