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2 years ago

Someone know how to do this Im very confusing about how to do it

Mathematics

1 answer:

Sidana [21]2 years ago

3 0

It would be e, because it went down 10 instead of 5

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If an object is dropped from a height of 178 feet, the function h(t)=-16t^2+178 gives the height of the object after t seconds.

svp [43]

Answer:

B. 3.34s

Step-by-step explanation:

Find t when the object hit the ground, h(t)=0.

h(t)=-16t²+178

0=-16t²+178

16t²=178

t²=11.125

t=√11.125=3.33541601603s

4 0

2 years ago

The Oregon Department of Health web site provides information on the cost-to-charge ratio (the percentage of billed charges that

Alekssandra [29.7K]

Answer:

We conclude that the mean cost-to-charge ratio for Oregon hospitals is lower for outpatient care than for inpatient care.

Step-by-step explanation:W

We are given with the cost-to-charge ratios for both inpatient and outpatient care in 2002 for a sample of six hospitals in Oregon below;

Hospital 2002 Inpatient Ratio 2002 Outpatient Ratio

1 68 54

2 100 75

3 71 53

4 74 56

5 100 74

6 83 71

Let $\mu_1$ = mean cost-to-charge ratio for outpatient care

$\mu_2$ = mean cost-to-charge ratio for impatient care.

SO, Null Hypothesis, $H_0$ : $\mu_1 \geq \mu_2$ {means that the mean cost-to-charge ratio for Oregon hospitals is higher or equal for outpatient care than for inpatient care}

Alternate Hypothesis, $H_A$ : $\mu_1 < \mu_2$ {means that the mean cost-to-charge ratio for Oregon hospitals is lower for outpatient care than for inpatient care}

The test statistics that would be used here is Two-sample t-test statistics because we don't know about population standard deviations;

T.S. = $\frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ ~ $t__n__1_+_n_2_-_2$

where, $\bar X_1$ = sample mean cost-to-charge Outpatient Ratio = $\frac{\sum X_1}{n_1}$ = 63.83

$\bar X_2$ = sample mean cost-to-charge Impatient Ratio = $\frac{\sum X_2}{n_2}$ = 82.67

$s_1$ = sample standard deviation for Outpatient Ratio = $\sqrt{\frac{\sum (X_1-\bar X_1 )^{2} }{n_1-1} }$ = 10.53

$s_2$ = sample standard deviation for Impatient Ratio = $\sqrt{\frac{\sum (X_2-\bar X_2 )^{2} }{n_2-1} }$ = 14.33

$n_1$ = sample of hospital for outpatient care = 6

$n_2$ = sample of hospital for outpatient care = 6

Also, $s_p=\sqrt{\frac{(n_1-1)s_1^{2}+(n_2-1)s_2^{2} }{n_1+n_2-2} }$ = $\sqrt{\frac{(6-1)\times 10.53^{2}+(6-1)\times 14.33^{2} }{6+6-2} }$ = 12.574

So, the test statistics = $\frac{(63.83-82.67)-(0)}{12.574 \times \sqrt{\frac{1}{6}+\frac{1}{6} } }$ ~ $t_1_0$

= -2.595

The value of t test statistics is -2.595.

Now, at 5% significance level, the t table gives critical value of -1.812 at 10 degree of freedom for left-tailed test.

Since, our test statistics is less than the critical value of t as -2.595 < -1.812, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the mean cost-to-charge ratio for Oregon hospitals is lower for outpatient care than for inpatient care.

8 0

3 years ago

Kasie has a square rug that has an area measuring 72.25 ft determine how long the rug is

solmaris [256]

Answer:

the rug is 8.5 feet

Step-by-step explanation:

7 0

2 years ago

A company that manufactures small canoes has a fixed cost of $24,000. It costs $100 to prod canoes produced and sold.) a. Write

jarptica [38.1K]

Answer:

240

Step-by-step explanation:

Given:

The cost function for canoes, c(x) = 24,000 + 100x

Revenue function for canoes, R(x) = 200x

here, x is the number of canoes sold

Fixed cost = $24,000

Cost of production = $100

now at break even point, Revenue = cost

thus,

200x = 24,000 + 100x

100x = 24,000

x = 240 canoes

Hence, at breakeven, the number of canoes sold is 240

3 0

2 years ago

Four equivalent forms of a quadratic function are given. Which form displays the zeros of function h?

taurus [48]

Step-by-step explanation:

As we know that $f$ is a polynomial function, the values of $x$ for which $f(x)=0$ are said to be the zeros of $f$ .

Factoring the polynomial equation, if it is eligible to get factored, setting each factor equal to zero and solving can determine the zeros.

So, it is clear from above that option A i.e. $h\left(x\right)=-4\left(x\:-\:2\right)\left(x\:+\:2\right)$ and option C i.e. $h\left(x\right)\:=\:4\left(x^2\:-\:4\right)$ displays the zeros of function h, as they can be factored by setting each factor equal to zero.

Option A)

Lets solve them to get the zeros of these functions.

Considering the function

$h\left(x\right)=-4\left(x\:-\:2\right)\left(x\:+\:2\right)$

$\mathrm{The\:roots\:are\:the\:intercepts\:with\:the\:x-axis}\:\left(y=0\right)$

$-4\left(x-2\right)\left(x+2\right)=0$

Using the Zero Factor Principle:

$\mathrm{ \:If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$

So,

$\mathrm{Solve\:}\:x-2=0:\quad x=2$

$\mathrm{Solve\:}\:x+2=0:\quad x=-2$

$\mathrm{The\:zeros\:to\:the\:quadratic\:equation\:are:}$

$x=2,\:x=-2$

Option B)

Considering the function

$h\left(x\right)\:=\:4\left(x^2\:-\:4\right)$

$\mathrm{The\:roots\:are\:the\:intercepts\:with\:the\:x-axis}\:\left(y=0\right)$

$4\left(x^2-4\right)=0$

$\mathrm{Divide\:both\:sides\:by\:}4$

$\frac{4\left(x^2-4\right)}{4}=\frac{0}{4}$

$x^2-4=0$

$x^2=4$

$\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}$

$x=\sqrt{4},\:x=-\sqrt{4}$

$x=2,\:x=-2$

Although the zeros of the function $h\left(x\right)=-4x^2\:+\:16$ can also be obtained for the function by similar method. But, for this we would have to solve them before determining the zeros.