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gulaghasi [49]
3 years ago
13

College students are offered a 8% discount on a textbook that sells for 26.50. If the sales tax is 8, find the cost of the textb

ook including sales tax.
Mathematics
2 answers:
aleksandr82 [10.1K]3 years ago
7 0
IF THE BOOK COSTS 26.50 AND YOU GET A DISCOUNT OF 8%, YOU NEED TO FIND OUT HOW MUCH IS 8% OF 26.50, WHICH IS IS 2.12 DISCOUNT
SO YOUR BOOK COSTS NOW 26.50-2.12=24.38
NOW, IF YOU WILL PAY 8% TAXES, EIGHT PERCENT OF 24.38 IS 1.95
YOUR BOOK WILL COST 24.38+1.95=26.33
Bingel [31]3 years ago
4 0

Answer:

26.3304

Step-by-step explanation:

Given,

The original price of the textbook = 26.50,

Also, the discount percentage = 8 %,

Thus, the price of the textbook after discount = 26.50 - 8 % of 26.50

=26.5-\frac{8\times 26.5}{100}

=26.5-2.12

=24.38

Now, the sales tax = 8 %,

Hence, the cost of the textbook including sales tax = 24.38 + 8 % of 24.38

=24.38+\frac{8\times 24.38}{100}

=24.38 + 1.9504

=26.3304

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In what year was her grandpa lopez twice as old as her dad?show how you know
RoseWind [281]
So,

We are trying to figure out when Grandpa Lopez's age was twice that of Dad.

Let x represent the number of years before/after when G. Lopez's age was twice that of Dad.

66 + x = 2(37 + x)

Distribute.
66 + x = 74 + 2x

Subtract x from both sides.
66 = 74 + x

Subtract 74 from both sides.
-8 = x

So 8 years ago, G. Lopez was twice as old as Dad.  Let's check that.

66 - 8 = 58

37 = 8 = 29

29 * 2 = 58
58 = 58

It checks.
8 0
3 years ago
YALL HELP I HAVE A EXAM ​
vekshin1

Answer:

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Step-by-step explanation:

8 0
3 years ago
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Rico sold 38 papers in 2 hours. at this rate how many papers would he sell in 3 hours.
lidiya [134]
19 per hour so 19 times 3 is 57
6 0
3 years ago
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The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a st
Alinara [238K]

Answer:

There is a 0.82% probability that a line width is greater than 0.62 micrometer.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. The sum of the probabilities is decimal 1. So 1-pvalue is the probability that the value of the measure is larger than X.

In this problem

The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a standard deviation of 0.05 micrometer, so \mu = 0.5, \sigma = 0.05.

What is the probability that a line width is greater than 0.62 micrometer?

That is P(X > 0.62)

So

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.62 - 0.5}{0.05}

Z = 2.4

Z = 2.4 has a pvalue of 0.99180.

This means that P(X \leq 0.62) = 0.99180.

We also have that

P(X \leq 0.62) + P(X > 0.62) = 1

P(X > 0.62) = 1 - 0.99180 = 0.0082

There is a 0.82% probability that a line width is greater than 0.62 micrometer.

3 0
2 years ago
A survey shows that 10% of the population is victimized by property crime each year. A random sample of 527 older citizens (65 y
jekas [21]

Answer:

The data provide sufficient evidence that older people are more likely to be victimized.

Step-by-step explanation:

H 0 : P = 0.10

H 1 : P > 0.10 (Right tailed test)

n = 527, P = 0.1235

The test statistics

x = P - p / \sqrt{p*(1-p) / n}

x = 0.1235 - 0.10 / \sqrt{0.10 * 0.90 / 527}

x = 0.0235 / \sqrt{0.09 / 527}

x = 0.0235 / \sqrt{0.00017077798}

x = 0.0235 / 0.0130682049264618

x = 1.798257689731729

x = 1.798

P value = [1 - p(Z > 1.7980] (Right tailed test)

P value = 0.036089

The P - Value is very small, so <u>reject H0</u>

Conclusion: The data provide sufficient evidence that older people are more likely to be victimized.

7 0
3 years ago
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