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3 years ago

5

I need help I’m bad at this algebra

1 answer:

GenaCL600 [577]3 years ago

8 0

You should get the app Socratic

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25 POINTS, I DONT UNDERSTANDDDDDD :C WHAT IS SO MISLEADING ABOUT THIS GRAPH???

Kisachek [45]

Answer:

honestly, the graph look totally fine...

If one ere pressed to find something to complain about it, one could suggest that you do not know if this was the starting price of the stock or the ending price of the stock each day?... One could also argue that to be a bit more meaningful you might want to know the range of prices during each day...

look up what is called a candle stick graph.. each day looks like a candlestick... the top is the highest value each the bottom the lowest, and there is a line in the candle that shows the closing price

Step-by-step explanation:

3 0

3 years ago

PLEASE ANSWERRRRRRR

Mademuasel [1]

Answer:

Step-by-step explanation:sorry

8 0

3 years ago

A sequence that changes by multiplying by the same number

zmey [24]

Answer: it never changes

7 0

3 years ago

In a group of 10 kittens, 5 are female. Two kittens are chosen at random. a) Create a probability model for the number of male

olya-2409 [2.1K]

Answer:

(b) Expected number of male kitten E(x) = 1

(c) Standard deviation is ± $\frac{2}{3}$ .

Step-by-step explanation:

Given that,

Number of kittens in a group are 10. Out of these 5 are female.

To find:- (a) create a probability model of male kitten chosen.

So, total number of kitten = 10

number of female kitten = 5

then, Number of male kitten = $10-5= 5$

Now total number of ways to choosing two kittens from group of 10 = $^{10} C_{2}$

= $\frac{10!}{2!\times8!}$

= $45$

for choosing (i) No male P(x=0) = P(Two female) = $\frac{^{5} C_{2}}{45}$

= $\frac{2}{9}$

(ii) 1 male P(x=1) = P(1 male and 1 female) = $\frac{^{5} C_{1}\times^{5} C_{1}}{45}$ = $\frac{25}{45}$ = $\frac{5}{9}$

(iii) 2 male P(x=2)= P(2 male) = $\frac{^{5} C_{2}}{45}$ = $\frac{2}{9}$

$x_{i}$ 0 1 2

P(X= $x_{i}$ ) $\frac{2}{9}$ $\frac{5}{9}$ $\frac{2}{9}$

(b) what is expected number of male kittens chosen ?

Expected number of male kitten E(x) = $o\times \frac{2}{9} + 1\times \frac{5}{9} + 2\times\frac{2}{9}$

= $1$

(c) what is standard deviation ?

$\sigma(x) = \sqrt{ (E(x^{2} )-(Ex)^{2})$

No,

$Ex^{2} =o\times \frac{2}{9} + 1\times \frac{5}{9} + 4\times\frac{2}{9}$

= $\frac{13}{9}$

$\sigma(x)=\sqrt{\frac{13}{9} - 1 }$ $=\sqrt{\frac{4}{9} }$

= ± $\frac{2}{3}$

6 0

3 years ago

Heather practices soccer and piano. Each day she practices piano for 2 hours. After 5 days, she practiced both piano and soccer

irina [24]

She practiced for 4 hrs
4×5=20

5 0

3 years ago