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My name is Ann [436]
3 years ago
9

Krepps Corporation produces a single product. Last year, Krepps manufactured 33,100 units and sold 27,800 units. Production cost

s for the year were as follows:
Direct materials $ 248,250
Direct labor $ 145,640
Variable manufacturing overhead $ 274,730
Fixed manufacturing overhead $ 595,800

Sales totaled $1,320,500 for the year, variable selling and administrative expenses totaled $164,020, and fixed selling and administrative expenses totaled $205,220. There was no beginning inventory. Assume that direct labor is a variable cost.
Under variable costing, the company's net operating income for the year would be _____.
Business
1 answer:
AfilCa [17]3 years ago
7 0

Answer:

The correct answer is $95,400 lower than absorption costing.

Explanation:

According to the scenario, the given data are as follows:

Units manufactured = 33,100

Sold units = 27,800

So, Units in ending inventory can be calculated as follows:

Units in ending inventory = Units manufactured - Sold units

= 33,100 - 27,800 = 5,300 units

Now, Fixed manufacturing OH = $595,800

So, we can calculate the fixed manufacturing OH per unit by using following formula:

Fixed manufacturing OH per unit = $595,800 ÷ 33,100 = $18

So, Difference in net income for the year can be calculated as follows:

Net income difference = Fixed manufacturing OH per unit × Units in ending inventory

= $18 × 5,300 units = $95,400

Hence, The net income in variable costing is $95,400 which is lower than in absorption costing.

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Answer:

Monthly rent of $345 would maximize revenue

Explanation:

Revenue = Price * Quantity

Quantity depends on price. We need to work out the relationship between price and quantity (that is, the demand function)

When the rent is $420, quantity demanded is 90 units:

When P = 420 we have Q = 90

Let x be the change in price. For every 3 dollar increase (decrease) in price demanded quantity will decrease (increase) 1 unit:

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To find the relationship between P and Q we seek to eliminate x.

Multiply both sides of (b) with 3 we have: 3Q = 270 - x (b')

From (a) and (b') we have: P + 3Q = 420 + x + 270 - x

=> P = 690 - 3Q

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To find maximum set derivative of R to 0:

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=> Q = 690/6 = 115

To lease 115 the price should be P = 690 - 3Q = 690 - 3*115 = 345

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