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dimulka [17.4K]
3 years ago
14

Emily leaves her house at exactly 8:25 a.m. to bike to her school, which is 3.42 miles away. When she passes the post office, wh

ich is 3/4 mile away from her home, she looks at her watch and sees that it is 30 seconds from 8:29 a.m. If Emily’s school starts at 8:50 a.m., can Emily make it to school on time without increasing her rate of speed? Show and/or explain the work necessary to support your answer.
Mathematics
1 answer:
mafiozo [28]3 years ago
8 0
First, let's find out the number of minutes Emily has to get to school. From 8:25 to 8:50, there are 25 minutes.

Next, let's find out  the number of minutes before Emily looks at her watch. From 8:25 to 8:28.50, there are 3.5 minutes.

Now let's calculate Emily's speed in miles per minute. To do so, divide the distance traveled by the time it took:

\frac{0.75}{3.5} miles/minute

Now let's calculate how far Emily can travel in 25 minutes going this speed. To do so, we multiply her speed by the time traveled:

\frac{0.75(25)}{3.5} =5.357 miles

5.357 miles is greater than 3.42 miles, so yes, Emily will make it to school on time.


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d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} \\d = \sqrt{(2--3)^2 + (1-6)^2} \\d = \sqrt{(5)^2 + (-5)^2} \\d = \sqrt{25 + 25} \\d = \sqrt{50} \\d=7.07

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d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} \\d = \sqrt{(9-2)^2 + (5-1)^2} \\d = \sqrt{(7)^2 + (4)^2} \\d = \sqrt{49 + 16} \\d = \sqrt{65} \\d=8.06

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d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} \\d = \sqrt{(9--3)^2 + (5-6)^2} \\d = \sqrt{(12)^2 + (-1)^2} \\d = \sqrt{144 + 1} \\d = \sqrt{145} \\d=12.04

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Complete question:

A market analyst is hired to provide information on the type of customers who shop at a particular store. A random survey is taken of 100 shoppers at this store. Of these 100, 73 are women. The shoppers The data is summarized below. we grouped in three age categories, under 30, 30 up to 50 and 50 and over. Women under 30 are 30, Men under 30 are 8 Women 30 to 50 are 25 and Men are 14 Women 50 and over are 18 and Men are 5.

Let W be the event that a randomly selected shopper is a woman. Let A be the event that a randomly selected shopper is under 30. a.) Find the probability of W. W (women Shoppers) = Find the probability of A. b.) Find the probability of A and W. c.) P (A and W) (Shoppers) d.) Find the probability of A or W. P(A or W) (Shoppers) e.) Find the probability of A given W

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- - - - - - - - Women Men Total

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Totals - - - - - - 73 - - -27 - - 100

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Probability : P= (required outcome / Total possible outcomes)

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P(W) = 73/100

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= number of shoppers under 30 = 38

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P(A) = 38/ 100

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(38 / 100 + 73 / 100 - 30 / 100) = (38+73-30) /100

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E) probability of A given W:

P(A n W) / P(W) = 30/73

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